Answer:
y 
y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction
Explicación paso a paso:
La ecuación cuadrática que tenemos es (4y - 3)² = 72
Debemos encontrar el valor de y.
Ahora, 4y - 3 = ± 6√2
⇒ 4y = 3 ± 6√2
⇒
y 
Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)
I will designate the hourly rate for weekdays as x and for weekends as y. The equations are arranged as follows:
13x + 14y = $250.90
15x + 8y = $204.70
This gives us a system of equations which can be solved by multiplying the first equation by 4 and the second by -7. This leads to:
52x + 56y = $1003.60
-105x - 56y = -$1432.90
By summing these two equations, we arrive at:
-53x = -$429.30 --> 53x = $429.30 --> (dividing both sides by 53) x = 8.10. This represents her hourly wage on weekdays.
Substituting our value for x allows us to determine y. I will utilize the first equation, but either could work.
$105.30 + 14y = $250.90. To isolate y, subtract $105.30 from both sides --> 14y = $145.60 divide by 14 --> y = $10.40
Thus, we find that her earnings are $8.10 per hour on weekdays and $10.40 per hour on weekends. The difference shows she earns $2.30 more on weekends than on weekdays.
This situation exemplifies the distributive property, where the number outside the parentheses impacts all the terms within through multiplication. Therefore, the resulting action here is:
<span>The 4 should be multiplied by each term found inside the parentheses.
</span>
Esto no puede ser correcto ya que si hay 60 coches, eso implica 240 ruedas de coches, y 25 bicicletas significan 50 ruedas de bicicletas, lo que suma un total de 290 ruedas. Si hubiera 1 coche adicional, habría 86 vehículos y 294 ruedas, o si se agregaran 2 bicicletas más, eso resultaría en 87 vehículos y 294 ruedas.
Response:
Each associate incurs a cost of $700 daily for the client, meaning that 'a' associates will cost the client 700a dollars each day. For each partner, the charge is $1500 daily, so 'p' partners will accumulate a cost of 1500p dollars daily. The cumulative bill amounts to 700a + 1500p = $14100:
700a + 1500p = 14100
700a + 1500p = 14100
Given that there are a total of 11 lawyers assigned (associates and partners), the equation a + p must equal 11.
a + p = 11
a + p = 11
\underline{\text{Formulate System of Equations:}}
Formulate System of Equations:
700a + 1500p =
700a + 1500p = 14100
14100
a + p = 11
11