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Ber
2 days ago
12

Use the chart to answer the following questions:)

Mathematics
1 answer:
zzz [4K]2 days ago
8 0

it’s $295.47 that’s everything

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What is the solution to the linear equation? 2.8y + 6 + 0.2y = 5y – 14 y = –10 y = –1 y = 1 y = 10
Zina [3917]

2.8y + 6 + 0.2y = 5y – 14

Start by simplifying the left side:

3y + 6 = 5y - 14

Next, deduct 3y from both sides:

6 = 2y - 14

Add 14 to both sides:

2y = 20

Now, divide by 2:

y = 20 / 2

y = 10

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a product online for $299 and was charged an additional $10 for shipping and handling. The customer received a rebate of $99 and
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The main span of Bridge A ​(2300 ​feet) is​ _____ percent shorter than the main span of Bridge B ​(4700 ​feet).
Svet_ta [4341]
To determine this answer, you need to calculate the percentage change.
This involves dividing the difference in lengths by the original length. We begin with the main bridge.

4700 - 2300 = 2400
2400 divided by 4700 equals approximately 51.1% shorter.
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11 days ago
At a large company, employees can take a course to become certified to perform certain tasks. There is an exam at the end of the
Leona [4187]

Answer:

A Type II error occurs when the null hypothesis is not rejected, even when the alternative hypothesis is actually valid.

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The implication is that the new method may be dismissed or altered despite it being a real enhancement.

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5 0
15 days ago
Evaluate ∫SF⃗ ⋅dA⃗ , where F⃗ =(bx/a)i⃗ +(ay/b)j⃗ and S is the elliptic cylinder oriented away from the z-axis, and given by x2/
Inessa [3926]

Respuesta:

Por lo tanto, la integral de superficie es \pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c.

Explicación paso a paso:

La función dada es,

\vec{F}=\frac{bx}{a}\uvec{i}+\frac{ay}{b}\uvec{j}

Para encontrar,

\int\int_{S}\vec{F}dS 

donde S=A=superficie del cilindro elíptico debemos aplicar el teorema de divergencia, así que,

\int\int_{S}\vec{F}dS

=\int\int\int_V\nabla.\vec{F}dV

=\int\int\int_V(\frac{b}{a}+\frac{a}{b})dV 

=\frac{a^2+b^2}{ab}\int\int\int_VdV

=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}

=\frac{a^2+b^2}{ab}\times \pi ab\times 2c=\pi (a^2+b^2)c

  • Si el vector unitario \cap{n} está dirigido en dirección positiva (hacia afuera), entonces z=c y,

\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1}. dA 

=\int\int_{S_1}.dA=0

  • Si el vector unitario \cap{n} está dirigido en dirección negativa (hacia adentro), entonces z=-c y,

\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA 

=\int\int_{S_2}. -dA=0

Por lo tanto, la integral de superficie sin el vector unitario de la superficie es,

\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c

5 0
8 days ago
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