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vagabundo
2 months ago
13

Christie has $200 in her bank account. Every month, she deposits $20 into her account. The equation of the line that models the

amount of money, y, in her account x years from now is y =    x=
Mathematics
2 answers:
Svet_ta [12.7K]2 months ago
7 0
Equation of the line that represents the amount of money y in her account x years from now. Step-by-step explanation: Christie has $200 in her account. Each month, she adds $20 to her account. Based on the given scenario: In 1 month, she deposits $20 and thus, in 1 year (which is 12 months), her total deposits equal = Let y indicate the total amount of money, and x will represent the years. Therefore, the equation modeling the amount of money y in her account after x years is;
Zina [12.3K]2 months ago
3 0
Each month she puts in 20......therefore annually she deposits (20 * 12) = 240 y = 240x + 200
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Jerry drove 10 miles in half the time it took Marcy to drive 10 miles. If jerry average speed was r miles per hour what was Marc
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Answer:

0.5r

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The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean
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Answer:

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549

Step-by-step explanation:

Given data and notation

\bar X=3.8 indicates the sample mean

s=0.5 refers to the sample standard deviation

n=15 is the sample size

\mu_o =4 represents the value we are testing.

\alpha indicates the significance level for the hypothesis test.

t refers to the statistic of interest.

p_v is the p-value for the test (the variable we are interested in).

Formulate the null and alternative hypotheses.

I will set up the hypotheses to verify if the mean weight falls below 4 ounces, formalizing:

Null hypothesis: \mu \geq 68

Alternative hypothesis: \mu < 4

Since our sample size is < 30 and the population standard deviation is unknown, it’s advisable to utilize a t test to compare the actual mean against the reference value, with the statistic calculated as follows:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)

t-test: "This test compares group means and is commonly utilized to determine if the mean is (greater than, less than, or not equal to) a specific value."

Calculate the statistic

We can substitute the provided information into formula (1):

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549 

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