An elevator in a hotel moves at 20 feet per second. leaving from the ground floor, its height in feet after t seconds is given b

Answer:

Her accumulated earnings for the month total $2208

Step-by-step explanation:

A dental lab technician receives $14 hourly for day shifts and $18 hourly for night shifts.

During one month:

She completed six 4-hour day shifts

Thus, total hours worked =

Three 8-hour day shifts =

Three 10-hour day shifts =

Total day hours = 24+24+30=78 hours

Hourly rate for daytime work = $14

Cost for 78 day hours =

Five 6-hour night shifts=

Four 8-hour night shifts =

Total night hours = 30+32=62 hours

Hourly rate for nighttime work = $18

Cost of 62 night hours =

Thus, total monthly earnings = $1092+$1116 = $2208

Consequently, her total pay for the month amounts to $2208

The provided equation is a differential equation that allows for variable separation. You should group similar terms, integrate, use the correct limits, and present V as a function of t. This is achieved in the following manner: dV/dt = -3(V)^1/2, which rearranges to dV/-3V^1/2 = dt. Initially, when V equals 225, after integration, we arrive at -2/3(√V - √225) = t, which can be further detailed as -2/3(√V - 15) = t. This represents the function for V at a specific time t. I trust this information is helpful, have a pleasant day.

Assuming a maximum rental duration of 8 days, if we apply this to the equation, Happy Harry's Rentals costs $500, while Smilin' Sam's charges $600. Therefore, for the 7th and 8th days, Happy Harry's Rentals is a better option, while Smilin' Sam's is preferable for the first six days.

Explanation:

Step-by-step clarification:

Referring to step 6

(b² — 4ac) / 4a² = (x + b/2a)²

The mistake in the question is that it should be (x + b/2a)²

According to step 7

±√(b² —4ac) /2a = x + b/2a

The error in the question is that it should be divided by 2a, not 1a.

1. The transition from step 6 to step 7 involves taking the square roots of both sides

(b² — 4ac) / 4a² = (x + b/2a)²

Taking the square of both sides

√(b²—4ac) / √4a² = √(x + b/2a)²

√(b²—4ac) / 2a = x + b/2a

This forms step 7 correctly.

Next, subtracting b/2a from both sides

√(b²—4ac) / 2a - b/2a= x + b/2a -b/2a

√(b²—4ac) / 2a — b/2a = x

(√(b²—4ac)  — b)/2a = x

x = [—b ± √(b²—4ac)] / 2a

This gives the desired formula.

The discriminant is D = b²—4ac.

The given road capacity is 3,500 vehicles per hour, and the expected number of vehicles arriving is 14,000. To calculate the time required for these vehicles to access the arena:
14,000 vehicles divided by 3,500 vehicles per hour equals 4 hours.

If the event is scheduled to commence at 7 p.m., the roads should close at: 7 p.m. minus 4 hours, which results in 3 p.m.