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borishaifa
2 months ago
5

At a large company, employees can take a course to become certified to perform certain tasks. There is an exam at the end of the

course that needs to be passed for certification. The current pass rate is 0.7, but a new program is being tested to help increase the pass rate. The null hypothesis of the test is that the pass rate for the new program is 0.7. The alternative is that the pass rate for the new program is greater than 0.7. What is the Type Il error and the consequence that could result from the test?
Mathematics
1 answer:
Leona [12.6K]2 months ago
5 0

Answer:

A Type II error occurs when the null hypothesis is not rejected, even when the alternative hypothesis is actually valid.

<pin this="" scenario="" it="" suggests="" that="" the="" new="" program="" genuinely="" improves="" pass="" rate="" yet="" sample="" size="" is="" insufficient="" statistical="" evidence="" to="" prove="" it.="" consequently="" null="" hypothesis="" remains="" accepted.="">

The implication is that the new method may be dismissed or altered despite it being a real enhancement.

Step-by-step explanation:

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Here’s the answer below.

Step-by-step explanation:    

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57.2 g

Step-by-step explanation:

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Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract
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Answer:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Detailed solution:

Given:

The problem to solve is:

x^2=-5x+8

Convert the equation into the standard quadratic form ax^2+bx +c =0, where a,\ b,\ and\ c represent constants.

So, by adding 5x-8 to both sides, we get:

x^2+5x-8=0

Note that a=1,b=5,c=-8.

The roots of this quadratic are found by applying the quadratic formula given as:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a=1,b=5,c=-8 into the formula and calculate for x.

x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Hence, the roots are:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

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Explanation:

Step-by-step clarification:

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The mistake in the question is that it should be (x + b/2a)²

According to step 7

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The error in the question is that it should be divided by 2a, not 1a.

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Taking the square of both sides

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This forms step 7 correctly.

Next, subtracting b/2a from both sides

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