Answer:
The function takes negative values for all real x where
–6 < x < –2
Detailed explanation:
the function f(x) = (x + 2)(x + 6)
Let's find the x intercepts of the function
0 = (x+2)(x+6)
x+2=0, resulting in x=-2
x+6 = 0 giving x=-6
The x intercepts are -6 and -2
Now, we will draw a number line using the x intercepts, creating 3 intervals
- infinity to -6, -6 to -2 and -2 to infinity
Next, select a number from each interval to evaluate with f(x)
For x<-6, choose -7
f(-7) = (x + 2)(x + 6)
f(-7)=(-7 + 2)(-7 + 6) =5, which is positive
–6 < x < –2, choose -4
f(-4)=(-4 + 2)(-4 + 6) =-4, which is negative
For x>-2, choose 0
f(0)=(-0+ 2)(0 + 6) =12, which is positive
The function is negative for all real x where
–6 < x < –2