All categories

2 days ago

Estimate the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20.

Physics

1 answer:

ValentinkaMS [1.1K]2 days ago

7 0

The refrigerator's power consumption is as follows:

$P = 700 W$

If the refrigerator operates for 10 hours daily, the total monthly usage will be calculated as:

$t = 10 * 30 = 300 h$

Consequently, the overall energy consumed in a month is expressed as:

$E = P * t$

$E = 700 * 300$

$E = 210000$

$E = 210 kWh$

It’s noted that the price of one kWh is $0.20, leading to the total cost for one month being:

$C = $0.20 * 210$

$C = $42$

You might be interested in

A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum e

kicyunya [1011]

Answer:

Maximum emf = 5.32 V

Explanation:

Provided data includes:

Number of turns, N = 10

Radius of loop, r = 3 cm = 0.03 m

It made 60 revolutions each second

Magnetic field, B = 0.5 T

We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:

$\epsilon=\dfrac{d(NBA\cos\theta)}{dt}\\\\\epsilon=NBA\dfrac{d(\cos\theta)}{dt}\\\\\epsilon=NBA\omega \sin\omega t\\\\\epsilon=NB\pi r^2\omega \sin\omega t$

For the maximum emf, $\sin\omega t=1$

Therefore,

$\epsilon=NB\pi r^2\omega \\\\\epsilon=NB\pi r^2\times 2\pi f\\\\\epsilon=10\times 0.5\times \pi (0.03)^2\times 2\pi \times 60\\\\\epsilon=5.32\ V$

Hence, the maximum emf generated in the loop is 5.32 V.

3 0

8 days ago

Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and

Softa [904]

A force of 110 N is applied at an angle of 30° to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.

For the component parallel to the ground:
x = rcosβ
x = 110cos30°
x = 95.26

For the component perpendicular to the ground:
y = rsinβ
y = 110sin30°
y = 55

3 0

6 days ago

Read 2 more answers

An automobile is traveling at a constant 15 m/s, then it undergoes acceleration from that moment forward. Which statement best d

ValentinkaMS [1138]

Answer:

Explanation:

7 0

13 days ago

The iron ball shown is being swung in a vertical circle at the end of a 0.7-m string. how slowly can the ball go through its top

Keith_Richards [1021]

A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack. centripetal force = weight of the ball m v^2 / r = m g v^2 / r = g v^2 = g r v = sqrt { g r } v = sqrt { (9.80~m/s^2) (0.7 m) } v = 2.62 m/s Thus, the minimum speed for the ball at the top position is 2.62 m/s.

6 0

6 days ago

A car rolls down a ramp in a parking garage. The horizontal position of the car in meters over time is shown below. Graph of ver

Ostrovityanka [942]

Answer:

d_total = 12 m

Explanation:

In this kinematics scenario illustrated in the graph provided, we determine the distance traveled over a 24-second duration.

The comprehensive distance can be calculated as follows:

d_total = d₁ + d₂ + d₃

Given that d₂ on the graph is level (v=0), its distance equates to zero, hence d₂ = 0.

The distance for d₁ is calculated as:

d₁ = 12 - 6 = 6 m

For distance d₃:

d₃ = 6 - 0 = 6 m

Thus, the overall distance covered is:

d_total = 6 + 0 + 6

d_total = 12 m

3 0

2 days ago