State two advantages of a lead-acid accumulator over a leclanche cell​

Response:

n (a sin θ) = m λ₀

Since n > 1, this indicates that the fringes separate further apart

Clarification:

In a diffraction experiment, the equation for constructive interference fringes is provided by

a sin θ = m λ₀

It is presumed that the air has been evacuated from the experiment, setting n = 1

When this experiment is conducted in water, the wavelength alters

λₙ = λ₀ / n

for achieving constructive interference

a sin θ = m λₙ

we replace

a sin θ = m λ / n

n (a sin θ) = m λ₀

Given that water's refractive index is n = 1.33, the distance between the fringes increases due to n > 1, causing the fringes to move apart

1) The projectile's motion follows
,
In order to determine the velocity, we must compute the derivative of h(t): Next, we will compute the speed at t=2 s and t=4 s: The negative value of the second speed suggests that the projectile has already attained its highest point and is now descending. 2) The maximum height of the projectile occurs when its speed equals zero: Thus, we have And solving yields


3) To determine the maximum height, we substitute the time at which the projectile reaches this peak into h(t), specifically t=2.30 s: 4) The time at which the projectile lands is when the height reaches zero; h(t)=0, which leads to This results in a second-degree equation, producing two answers: the negative root can be disregarded as it lacks physical significance; the second root is

, which indicates the landing time of the projectile. 5) The moment the projectile impacts the ground corresponds to the velocity at time t=4.68 s:

, carrying a negative sign to denote a downward direction.

The density of mercury in its liquid form is


We understand that the equation determining the pressure at the base of a fluid column can be expressed through Stevin's law

where
represents the density of the liquid
g signifies the acceleration due to gravity
h indicates the height of the fluid column

Given that the pressure at the lower section of the beaker is , we can manipulate the preceding formula to calculate the height of the mercury column

Answer:

Explanation:

the provided information includes,

the charge of each of the two spherical drops = 0.1 nC

the potential on the surface = 300 V

when the drops combine into a larger drop

what is the surface potential of the new combined drop =?

radius = 0.003 m

volume =

=

= 2.612 × 10⁻⁷ m³

R = 0.00396 m

Response:

The water level in the pond will decrease.

Explanation:

According to Archimedes' principle, an object floating displaces a volume of water equivalent to its weight, while an object resting on the bottom displaces an amount of water that corresponds to its volume.

When the anchor is aboard the boat, it acts as a floating object, and when it rests at the pond's bottom, it becomes a submerged object.

Due to the anchor's weight and density being greater than water, the amount of water displaced when it's in the boat exceeds the amount displaced when it is on the bottom of the pond since the anchor's volume is minimal.

Thus, once the anchor is dropped to the bottom, the pond's water level will decrease. If the anchor remains suspended, it continues to displace water as a floating body, causing no change, but once it contacts the pond's bed, the water level drops.

I hope this clarifies!