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anzhelika
1 month ago
13

A team of engineering students is testing their newly designed raft in the pool where the diving team practices.

Physics
1 answer:
Yuliya22 [3.3K]1 month ago
6 0

Answer:

Lower than

Explanation:

When the cube is placed on the raft, the displaced water equals the combined weight of both the cube and raft. In contrast, when submerged in water, the displaced water corresponds to the raft's weight plus the cube's volume. Since the cube's volume is smaller than what is needed to displace its weight with water, the water level is lower.

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A 68 kg hiker walks at 5.0 km/h up a 9% slope. The indicated incline is the ratio of the vertical distance and the horizontal di
Softa [3030]

The formula used to calculate power is:

Power = Work / Time

Where Work is defined as Force multiplied by Distance, hence:

Power = Force * Distance / Time

This can also be expressed as:

Power = Force * Velocity<span>


Converting the velocity from km/h to m/s:</span>

Velocity = (5 km / h) (1000 m / km) (1 h / 3600 s)<span>
Velocity = 1.39 m/s 

</span>

The calculated force corresponds to the vertical component of the hiker's weight:

Force = Wy * g = W * sin θ * g

 

To find the angle θ, we utilize the slope, which is defined as:

slope = tan θ = ratio of vertical to horizontal distance

tan θ = 0.09

θ = 5.14˚

Thus, we have Force = 68 kg * sin(5.14˚) * 9.8 m/s²<span>
Force = 666.4 * sin(5.14) = 59.73 N 

</span>

<span>Now, let's compute the power:
<span>Power = 59.73 N * 1.39 m/s = 82.96 W
Given the hiker's efficiency is at 25%, we can find the metabolic power: 
<span>Metabolic Power = 82.96 W / 0.25 = 331.83 watts </span></span></span>
6 0
1 month ago
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
kicyunya [3294]
Final temperature to determine: Given the following details, the calculations proceed as follows: Mass of the silver ring is m = 4 g, initial temperature is presented, and the heat released is Q = -18 J (indicating heat loss). The specific heat of silver is considered next to find the final temperature.
5 0
28 days ago
A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Igno
Ostrovityanka [3204]

Answer

Given data:

height of the dam = 15 m

effective area for water flow = 2.3 x 10⁻³ m²

Applying the principle of energy conservation:

m g h = \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v= \sqrt{2\times 9.8 \times 15}

v= \sqrt{294}

v = 17.15 m/s

water discharge

Q = A V

Q = 2.3 x 10⁻³ x 17.15

Q = 0.039 m³/s

3 0
1 month ago
A person on a cruise ship is doing laps on the promenade deck. on one portion of the track the person is moving north with a spe
kicyunya [3294]
The resulting motion can be determined using the Pythagorean theorem, as the two components (north and east) are at right angles. To find the direction, trigonometry is applied, yielding Ф=arctan(3.8/12)=17.57° north of east.
4 0
1 month ago
Read 2 more answers
A rock is dropped from the top of a tall building. The rock's displacement in the last second before it hits the ground is 46 %
inna [3103]

The height measures 69.68 m

Explanation:

Given data

Before striking the ground =  46 % of the total distance

To establish

the height

Solution

We know here acceleration and displacement, which is

d = (0.5)gt²..............1

Here d is the distance, g is the acceleration, and t is time

So, when an object falls it will be

h = 4.9 t²....................2

For the first part of the inquiry

The falling objects account for

54 % of the total distance

0.54 h = 4.9 (t-1)²...................3

Thus,

Now we possess two equations with unknown variables

We can equate both equations

The first equation already solves for h

Substituting h in the second equation allows us to find t

0.54 × 4.9 t² = 4.9 (t-1)²  

t = 0.576 s and  3.771 s

We choose here 3.771 s since 0.576 s is negligible; the distance covered in the last second before it impacts the ground is 46 % of the entire fall.

Thus, selecting t = 3.771 s

Then h from equation 2

h = 4.9 t²

h = 4.9 (3.771)²

h =  69.68 m

Thus, the height is 69.68 m

6 0
1 month ago
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