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sladkih
2 months ago
14

A book shelf holds twenty books. Eleven are hard- covered, nine of the books are nonfiction, and four of the nonfiction books ar

e hard-covered, as shown in the Venn diagram. Let event H be a hard-covered book and let event N be a nonfiction book
Mathematics
2 answers:
PIT_PIT [12.4K]2 months ago
7 0

Results: 4/20

11/20

4/11

Detailed explanation:

tester [12.3K]2 months ago
7 0

Answer:

1) Determine the likelihood that a selected book is a nonfiction hard cover. P(N ∩ H) = 4/20

2) Calculate the probability of picking a hard-covered book. P(H) = 11/20

3) Compute the conditional probability. = 4/11

---------------------------------------------------------------------------------------------

1.) 4/20

2.) 11/20

3.) 4/11

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A line contains (34,12) and (32,48) what is the slope of the line in simplified form? HELP ASAPl
Zina [12379]

Response:

m=-18

Step-by-step explanation:

1. The line includes the points (34,12) and (32,48). Then, apply the slope formula, which is:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

2. By substituting values into the formula, you will get:

y_{2}=48\\y_{1}=12\\x_{2}=32\\x_{1}=34

m=\frac{48-12}{32-34}\\m=\frac{36}{-2}\\m=-18

4 0
2 months ago
.580 80 repeating as fraction
Svet_ta [12734]
To start, we will shift the non-repeating segment of the decimal to the left side by dividing by a power of 10.

Then we will assign a variable to represent the value and also shift the repeating segment to the left.

Essentially, the concept here is that we can denote the repeating portion with a variable, let's say "x", and move forward with the calculation;

\bf 0.580\overline{80}\implies \boxed{\cfrac{5.80\overline{80}}{10}}\qquad \textit{now, let's say }x= 5.80\overline{80}\\\\
-------------------------------

\bf thus\qquad \begin{array}{llll}
100\cdot x&=&580.80\overline{80}\\
&&575+5.80\overline{80}\\
&&575+x
\end{array}\qquad \implies 100x=575+x
\\\\\\
99x=575\implies x=\cfrac{575}{99}\qquad therefore\qquad \boxed{\cfrac{5.80\overline{80}}{10}}\implies \cfrac{\quad \frac{575}{99}\quad }{10}
\\\\\\
\cfrac{\quad \frac{575}{99}\quad }{\frac{10}{1}}\implies \cfrac{575}{99}\cdot \cfrac{1}{10}\implies \cfrac{575}{990}\implies \stackrel{simplified}{\cfrac{115}{198}}

you can verify that using your calculator.
4 0
2 months ago
Read 2 more answers
Based on daily measurements, Bob's weight has a mean of 200 pounds with a standard deviation of 16 pounds, while Mary's weight h
babunello [11817]

Answer:

(C) They have the same coefficient of variation

Step-by-step explanation:

The coefficient of variation (CV) is calculated using the formula:

CV = \frac{\sigma}{\mu}

Where \sigma represents standard deviation and \mu represents the mean.

Bob's average weight is 200 pounds with a standard deviation of 16 pounds

This indicates that \sigma = 16, \mu = 200.

Thus, his coefficient of variation is

CV = \frac{16}{200} = 0.08

Mary's average weight is 125 pounds, with a standard deviation of 10 pounds.

This implies \sigma = 10, \mu = 125

Therefore, her coefficient of variation is

CV = \frac{10}{125} = 0.08

Since both have the same coefficient of variation, the accurate response is.

(C) They have the same coefficient of variation

6 0
2 months ago
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