Use the table to find the residual points. A 4-column table with 5 rows. The first column is labeled x with entries 1, 2, 3, 4,

Answer:

Triangles would be congruent through ASA if Angle A is equal to Angle T.

Triangles would be congruent via AAS if Angle B matches Angle P.

Step-by-step explanation:

It is established that sides AC and TQ are congruent, along with angles BCA and PQT. If angles A and T are equal, we apply the ASA theorem. Similarly, if angle B equals angle P, we reference the AAS theorem.

Since only two options need to be selected, you can conclude your options there.

Answer:

Part A:

x+y= 95

x = y+25

Part B: 35 minutes

Part C: No

Step-by-step explanation:

• Part A:

Eric spends a total of 95 minutes daily playing basketball and volleyball combined.

x+y= 95

Where:

x =minutes Eric plays basketball

y = minutes he allocates to volleyball

He dedicates 25 minutes more to basketball compared to volleyball.

x = y+25

Equations are:

x+y= 95

x = y+25

• Part B:

Substituting x=y+25 into the first equation yields:

(y+25) + y =95

Solving for y

y+25+y =95

25+2y=95

2y=95-25

2y=70

y = 70/2

y = 35 minutes

Part C: No

If x = 35

x+y= 95

35+y =95

y= 95-35

y = 60 minutes

Inserting y=60 into the other equation:

x = y+25

35 = 60+25

35 ≠85

Response:

B. 255 m

Detailed breakdown:

utilize similar triangles

L / 60 = 85 / 20

L = (85 * 60) / 20

L = 255 m

To solve this problem, simply sum all of the grocery expenses and then divide that total by 4...

*Refer to the image attached below

Answer:

346.4 ft

Step-by-step Explanation:

The distance between the boats, CD = BD - BC

Using trigonometry, find the length of BD in triangle ∆ABD and also calculate the length of BC in triangle ABC.

Length of BD in triangle ABD:

Opposite side to <30° = 300 ft

Adjacent side = BD

Divide both sides by tan(30)

(rounded to nearest tenth)

Length of BC in triangle ABC:

Opposite side to <60° = 300 ft

Adjacent side = BC

Divide both sides by tan(60)

(rounded to nearest tenth)

The distance, CD, between the boats is calculated as BD - BC

= 519.6 - 173.2 = 346.4 ft