Answer: 13 liters
Explanation: It is crucial to remember two factors that allow us to carry out this calculation.
Firstly, temperature and pressure must remain unchanged, so these constant values are not considered when calculating volume since they will always be the same.
Secondly, we are dealing with the same gas, with the conditions remaining consistent. Hence, we can proceed.
For 1.2 moles of gas, we have a volume of 8.5 liters. Now, let's determine the volume for 0.65 moles:
0.65 mole * (8.5 liter / 1.2 mole) = 4.25 liters
As we maintain the same gas type, we simply need to total the volumes for each mole amount:
8.5 liters + 4.25 liters = 12.75 liters, which rounds to 13 liters.
Response:
This is my understanding.
Explanation:
(g) Titration curves
While I can't create two curves on a single graph, I can depict them separately for clarity.
In part (d), the graph indicated an equivalence point at 20 mL.
For the second titration, since the NaOH concentration is doubled, the volume to reach the equivalence point will be halved — 10 mL.
Below are the two titration curves.
(h) Evidence of reaction
Both HCl and NaOH are colorless solutions.
There is no gas released or precipitate formed during their reaction.
It’s likely the student observed that the Erlenmeyer flask heated up, indicating a chemical change.
1.22 mg is equivalent to 0.022 grams. Since one gram contains 1000 mg, convert milligrams to grams by dividing by 1000. Calculate volume using mass divided by density: volume equals 0.022 grams divided by 0.754 grams/cm³, resulting in approximately 0.029 or 0.03 cm³. Additionally, weight in newtons equals the mass in kilograms multiplied by gravitational acceleration: weight equals 10 kg times 9.8 m/s², which is 98 newtons.
Answer:
The answer is 7160 cm
Explanation:
Given Data
Diameter = 1 mm
Length =?
Quantity of gold = 1 mol
Density = 17 g/cm³
Steps
1.- Obtain the atomic mass of gold
Atomic mass = 197 g
This means 197g ------------ 1 mol
2.- Find the volume of the wire
Density = mass/volume
Volume = mass/density
Volume = 197/17
Volume = 5.7 cm³
3.- Calculate the wire length
Volume = πr²h
Rearranging for h
h = volume / πr²
Radius = 0.05 cm
Substituting values
h = 5.7/(3.14 x 0.05²)
h = 5.7 / 0.0025
h = 7159.2 cm ≈ 7160 cm
Answer:
The sample with more oxygen atoms is a glass stirring rod.
Explanation:
Referring to the periodic table,
the glass stirring rod is composed of Silicon dioxide whereas the cotton ball is made of cellulose.
The molar mass of the glass stirring rod
= 60.08 grams/mole.
The molar mass of the cotton ball
= 162.09 grams/mole.
Considering the total number of molecules for oxygen is 32,
therefore,
In the glass stirring rod,
oxygen atoms contained in 5g =
= 2.66 g of oxygen
= 
= 0.16625 moles
= 0.16625 x 
=
atoms
In the cotton ball,
oxygen atoms contained in 5g = 
= 2.467 g of oxygen
= 
= 0.15418 moles
= 0.15418 
= 0.928 
Thus, the glass stirring rod has a greater quantity of oxygen atoms.