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DerKrebs
26 days ago
5

How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of

Chemistry
1 answer:
eduard [2.5K]26 days ago
4 0

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

  • The solution's volume is 350 mL
  • The solution's molarity is 2.75 M
  • The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

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Answer:

Explanation:

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I suspect this is related to the isotopes.
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20 days ago
The density of a 50% solution of naoh is 1.525 g/ml. what volume of a solution that is 50% by weight naoh is required to make 0.
eduard [2520]
We assume that the stated 50% is measured by volume. Molarity defines the concentration in terms of moles of solute per volume of solution.

      To find the moles of NaOH, use: (0.1 moles / L)(0.4 L)
                      n = 0.04 moles of NaOH

Assuming we start with 1 mL of 50% NaOH solution, 
  
                        (1 mL solution)(1.525 g/mL)(0.50) = 0.7625 g
Then, the number of moles calculates as follows,[
                  0.7625 g NaOH x (1 mol / 40 g) = 0.01906 moles of NaOH

                The volume of solution required can be determined by:(0.04 moles of NaOH)(1 mL solution / 0.01906 moles of NaOH)
                 
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Answer: 2.09 mL
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