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Andrews
2 months ago
6

At intermission, Xavier sold refreshments. Of the items he had, 1/5 were granola bars and 1/2 the remaining items were container

s of popcorn. The rest were divided equally among apples, rice cakes, and containers of yogurt. Xavier sold the 8 apples he had. How many items did he originally have?
Mathematics
2 answers:
lawyer [12.5K]2 months ago
4 0
The solution to this problem amounts to 60 items; if you'd like to know how I arrived at this conclusion, simply ask me.
Inessa [12.5K]2 months ago
4 0

Answer: He originally had 80 items.

Step-by-step explanation:

The information provided states that

A portion of the refreshments was granola = \dfrac{1}{5}

A portion of the refreshments was popcorn = \dfrac{1}{2}

The remainder would be

1-(\dfrac{1}{5}+\dfrac{1}{2})\\\\=1-\dfrac{7}{10}\\\\=\dfrac{10-7}{10}\\\\=\dfrac{3}{10}

Since the rest were evenly split between apples, rice cakes, and yogurt.

Count of apples sold = 8

Denote the total number of items as 'x'.

The question leads to this equation,

\dfrac{3}{10}\times \dfrac{1}{3}x=8\\\\\dfrac{x}{10}=8\\\\x=80

This means he started with 80 items.

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