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12345
1 day ago
12

What is the value of x in the equation 4 x plus 8 y equals 40, when y equals 0.8? 4.6 8.4 10 12What is the value of a in the equ

ation 3 a plus b equals 54, when b equals 9? 15 18 21 27What is the value of a in the equation 3 a plus b equals 54, when b equals 9? 15 18 21 27
Mathematics
2 answers:
AnnZ [3.9K]1 day ago
8 0

Answer:

1. 8.4 2. 15

Step-by-step explanation:

1. 4x + 8y = 40

when y = 0.8

4x + 8 × 0.8 = 40

4x = 40 - 8 × 0.8

4x = 40 - 6.4 = 33.6

....x = 33.6 / 4 = 8.4

2. 3a + b = 54

when b = 9

3a + 9 = 54

3a = 54 - 9

3a = 45

.....a = 45 / 3 = 15

please rate me

lawyer [4K]1 day ago
7 0

Answer:

a = 15

Step-by-step explanation:

Given

3a + b = 54 ← substitute b = 9

3a + 9 = 54 ( subtract 9 from both sides )

3a = 45 ( divide both sides by 3 )

a = 15

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One square has an area that is 10 cm2 larger than another. What is a reasonable domain for the area of the larger square?
Inessa [3926]

Answer:

R>10 reflects the required domain.

Step-by-step explanation:

We have two squares provided

Let the area of the larger square be denoted as x

The area of the smaller square is given, and we need to determine the domain for the larger square's area.

The domain refers to the possible values that x can assume in a function

In this context, x represents the area of the larger square

Because the area of the smaller square is 10cm^2

The area of the larger square must exceed 10cm^2

The domain will consist of all real numbers greater than 10

Mathematically, R>10 indicates the required domain.

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4 days ago
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lawyer [4039]

Answer:

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Step-by-step explanation:

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14 days ago
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do you agree that the equation (x-4)²=9 can be solved both by factoring and extracting square roots? ​
Zina [3917]

Given parameters:

  Equation:

          (x-4)²=9

Problem: Solve the equation by both factoring and extracting the square root.

Solution:

    Starting equation:

                  (x-4)²=9

         Subtracting 9 from both sides brings us to zero;

                (x-4)² - 9 = 0

                (x -4)² - 3² = 0

  This fits the concept of the difference of squares;

          x² - y² = (x + y)(x-y)

                     

Let x  = x-4 and y = -3

  Then input and solve;

              (x - 4 -3)(x - 4 -(-3)) = 0

              (x - 7)(x - 1) = 0

S thus,

             x - 7 = 0 or x-1 = 0

             x = 7 or 1

<pBy extracting the square roots;

          (x-4)² = 9

         √(x-4)² = √9

              x - 4 = 3

              x  = 4 + 3 = 7; however, this is not the sole solution

Thus, direct extraction of the square root is not the method for complete solutions.

7 0
11 days ago
Brandon purchased a new guitar in 2012. The value of his guitar, t years after he bought it, can be modeled by the function A(t)
Zina [3917]

Answer: The guitar's value over time is described by the 0.95 metric, indicating a 5% annual depreciation.

Step-by-step explanation:

To address this inquiry, we use an exponential decay formula:

A = P (1 - r) t

Where:

P = initial price

r = the reduction rate (expressed as a decimal)

t = time in years

A = price after t years

Substituting the known values:

A(t)=145(0.95)t.

Where

0.95 = 1-r

0.95-1 = r

-0.05 = -r

0.05 = r

Converted to percentage:

0.05 x 100 = 5%

Please reach out if further clarification is needed or if something was unclear.

6 0
13 days ago
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babunello [3666]

Answer:

The charge for the first three hours is $4 per hour.

Subsequently, the rate decreases to $2 per hour until the sixth hour.

Between the sixth and tenth hours, the cost is reduced further to $1 per hour.

The maximum charge for renting the bike is $30.

Step-by-step explanation:

The incline on the graph indicates the hourly rate for the bike rental.

During the initial three hours, the rental fee rises by $4 for each hour.

From the third to the sixth hour, the graph’s slope indicates a rate of $2 per hour for the rental.

The charge drops to $1 per hour from the sixth to the tenth hour.

After the tenth hour, the price, P, remains constant. The highest fee for the bike rental is $30.

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1 day ago
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