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Snowcat
1 month ago
13

During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16

t2 + 56t and h = -16t2 + 156t - 248, where t is the time that has passed since the first ball was hit.
Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

Sample response: Use substitution to set the equations equal to each other. Solve the resulting linear equation for time, t = 2.48 s. Substitute 2.48 into an equation to find the height, h.
Mathematics
2 answers:
Svet_ta [12.7K]1 month ago
6 0
To determine when both balls have the same height, equate the two equations and solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can eliminate the -16t^2 terms leading to
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Substituting this t value into either equation will provide the height.
h = 16(2.48)^2 + 56(2.48)
Final response:
h = 40.4736
I hope this assists you:)
Inessa [12.5K]1 month ago
4 0

The answer for ed+ is 40.5

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Rita is spending more time at home to study and practice math. Her efforts are finally paying off. On her first assessment she s
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Response

After her seventh assessment, she will score above 85.

Explanation

We can represent this situation through a linear equation.

On her initial assessment, Rita scored 58, providing the first point (1, 58).

On her second assessment, Rita earned 63, making our second point (2, 63).

To calculate the rate, known as the slope of our line, we utilize the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

(x_{1},y_{1}) signifies the coordinates for the first point

and (x_{2},y_{2}) represents the coordinates for the second point.

From these points, we can establish that x_{1}=1, y_{1}=58, x_{2}=2, y_{2}=63. We will input the values into our slope equation:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{63-58}{2-1}

m=\frac{5}{1}

m=5

Now, we recognize that Rita's score grows by 5 points with every assessment.

To finalize the equation of our line, we apply the point-slope formula:

y-y_{1}=m(x-x_{1})

y-58=5(x-1)

y-58=5x-5

y=5x+53

Ultimately, we substitute y with 85 in our equation and solve for x to determine on which assessment she will achieve a score higher than 85:

85=5x+53

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x=\frac{32}{5}

x=6.4

Since a score of 0.4 assessments is not possible, she will exceed 85 after her seventh assessment.


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