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nignag
3 months ago
8

Which number can each term of the equation be multiplied by to eliminate the fractions before solving? m – negative StartFractio

n 3 Over 4 EndFraction m minus StartFraction one-half EndFraction equals 2 StartFraction one-fourth EndFraction m. = 2 + m 2 3 4 5
Mathematics
1 answer:
zzz [12.3K]3 months ago
7 0

Answer: To remove fractions prior to solving, each term in the equation must be multiplied by 4.

Step-by-step explanation:

Consider the given expression:

-\frac{3}{4}m-\frac{1}{2}=2+\frac{1}{4}m

It is essential to simplify this before attempting to solve it.

Since the denominators differ, identifying the Least Common Denominator (LCD) is necessary.

Break down the denominators into their prime components:

4=2*2=2^2\\2=2

Select 2^2, as it possesses the greatest exponent. Thus:

LCD=2^2=4

Ultimately, to remove the fractions before solving, multiply both sides by 4:

(4)(-\frac{3}{4}m)-(4)(\frac{1}{2})=(4)(2)+(4)(\frac{1}{4}m)\\\\-3m-2=8+m

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. A hawk drops its prey from a certain height above the ground.The height, h metres, of the prey can be modelled by h = 4 + 11 t
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Answer:

The hawk releases the prey from a height of 4 meters.

It takes the prey 4 seconds to reach the ground.

Step-by-step explanation:

The equation gives insights about the height of the prey at any time starting from the moment it is dropped. Thus, to determine the drop height, we evaluate the expression at time equals zero (the drop moment). This answers the first question:

h=4+11t-3t^2\\h=4+11\,(0)-3\,(0)^2\\h=4\, \,meters

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This results in a quadratic equation that can be solved via the quadratic formula:

h=4+11t-3t^2\\0=4+11t-3t^2\\-3t^2+11t+4=0\\t=\frac{-11+-\sqrt{11^2-4\,(-3)(4)} }{2\,(-3)} \\t=\frac{-11+-\sqrt{121+48} }{-6} \\t=\frac{-11+-13 }{-6} \\t= 4\,\,and \,\, t=-\frac{1}{3}

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1 month ago
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If m<9=97° and m<12=114°, find each measure. I have to show my work.
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Solution/Step-by-step breakdown:

Information provided:

m<9 = 97°

m<12 = 114°

a. m<1 = m<9 because they are corresponding angles, which are equal.

m<1 = 97° (using substitution)

b. m<2 + m<1 = 180° (since they form a linear pair)

m<2 + 97° = 180° (substitute the value)

m<2 = 180 - 97 (subtracting 97 from both sides)

m<2 = 83°

c. m<3 = m<11 (as they are corresponding angles)

m<11 + m<12 = 180° (linear pair)

m<11 + 114° = 180° (substituting the known angle)

m<11 = 180 - 114

m<11 = 66°

m<3 = m<11 = 66°

d. m<4 + m<3 = 180° (linear pair)

m<4 + 66° = 180° (substituting the known angle)

m<4 = 180 - 66

m<4 = 114°

e. m<5 = m<2 as vertical angles are equal.

m<5 = 83° (using substitution)

f. m<6 = m<1 (vertical angles are equal)

m<6 = 97° (using substitution)

g. m<7 = m<4 (as vertical angles are equal)

m<7 = 114° (using substitution)

h. m<8 = m<3 (due to vertical angles being equal)

m<8 = 66° (using substitution)

i. m<10 = m<2 (corresponding angles are equal)

m<10 = 83° (using substitution)

j. m<11 = m<3 (because they are vertical angles)

m<11 = 66° (using substitution)

k. m<13 = m<5 (corresponding angles)

m<13 = 83° (applying substitution)

l. m<14 = m<9 (as vertical angles)

m<14 = 97° (applying substitution)

m. m<15 = m<12 (as vertical angles)

m<15 = 114° (applying substitution)

n. m<16 = m<11 (because they are vertical angles)

m<16 = 66° (applying substitution)

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