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andrey2020
17 days ago
12

A bouncing ball reaches a height of 27 feet at its first peak, 18 feet at its second peak, and 12 feet at its third peak. Descri

be how a sequence can be used to determine the height of the ball when it reaches its fourth peak.
Mathematics
2 answers:
Zina [3.9K]17 days ago
9 0

Sample response from E2020:

The successive heights drop by a factor of 2/3, so the series of peak heights is geometric: 27, 18, 12. Taking two-thirds of 12 yields 8, so the ball will reach 8 feet on the fourth peak.

I hope this is helpful :)

~ V.

tester [3.9K]17 days ago
4 0
A geometric sequence models the bounce heights:
Use the formula
A (subscript n) = Ar(n-1)
a = the first-term value
n = the index of the term you want (for the fourth peak, n = 4) 
r = common ratio, found by dividing the second term by the first
Here r = 18/27 = 2/3 because 27×(2/3) = 18, and similarly 18×(2/3) = 12
For the fourth peak n = 4
Compute: 4th term = 27(2/3)^(4-1) = 8
Therefore the height at the fourth peak is 8
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A.

Step-by-step explanation:

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13 days ago
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Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

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* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

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∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

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