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Anna35
9 days ago
14

What type of triangle has side lengths of 4√5, √145 and 19?

Mathematics
1 answer:
tester [3.8K]9 days ago
5 0

a, b, c - side lengths (a ≤ b ≤ c)

If a^2+b^2 < c^2, it forms an Obtuse triangle.

If a^2+b^2=c^2, it constitutes a Right triangle.

If a^2+b^2 > c^2, it describes an Acute triangle.

a=4\sqrt5,\ b=\sqrt{145},\ c=19\to a < b < c

Verify that the sum of the lengths of the first two sides exceeds that of the third.

a+b=4\sqrt5+\sqrt{145}\approx9+12=21 > 19=c\\\\CORRECT

a\neq b\neq c\neq a, thus identifying it as a Scalene triangle.

a^2=(4\sqrt5)^2=4^2(\sqrt5)^2=16(5)=80\\\\b^2=(\sqrt{145})^2=145\\\\c^2=19^2=361\\\\a^2+b^2=80+145=225 < 361=c^2\\\\a^2+b^2 < c^2

It qualifies as Obtuse triangle.

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