Driving from oban to stranraer a driver averages 8 miles per gallon of fuel. if fuel costs 83 cents a gallon how much will be th

0.30x represents the expense for the first soda type. 0.35(x+4) signifies the price for the second type of soda. Combine these amounts into an equation structured as:

Cost of Soda A + Cost of Soda B = Total Cost
0.30x + 0.35(x+4)=3.35 --> Expand 0.35(x+4)
0.30x + 0.35x + 1.4 = 3.35 --> Combine the x's and subtract 1.40.65x = 1.95 --> By dividing by 0.65, we find
x = 3

Samir purchases 3 cans of soda priced at 30 cents each and 7 cans (3+4) at 35 cents each. The overall total for Samir's soda is 10 cans.

Answer:

Step-by-step explanation:

The prices he received quotes for are as follows: $663, $273, $410, $622, $174, $374

To begin, we will find the average.

Average = total of data points/ number of data points.

Total of data points =

663 + 273 + 410 + 622 + 174 + 374

= 2516

Total count = 6

Average = 2516/6 = 419.33

Standard deviation = √summation(x - m)^2/n

summation(x - m)^2/n = (663 - 419.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2

= 179417.9334/6 = 29902.9889

Standard deviation = √29902.9889

= 172.9

In a pictorial graph, icons are utilized to depict the data presented. For instance, if a survey was conducted regarding food preferences at a barbecue, we might incorporate images of a hamburger, a hot dog, and a chicken leg. However, we cannot deduce the quantities involved merely by juxtaposing the icons.

Answer:

Wyjaśnienie krok po kroku:

Załóżmy, że prostokąt ma wierzchołki (x,y,z) w dodatnim oktancie.  Prostokątny pudełko musi być symetryczne względem wszystkich trzech osi.

Wtedy jego boki to

Objętość =

Maksymalizuj objętość przy założeniu

tj.

Użyj mnożników Lagrange'a, mamy

przy maksimum

Dzieląc otrzymujemy

Podobnie

Zatem otrzymujemy

Stąd wymiary to

(2x,2y,2z)

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Answer: CI = (0, 8)

Step-by-step explanation: The confidence interval for the difference in means is given as

Lower limit

= (x1 - x2) + margin of error

Upper limit

= (x1 - x2) - margin of error

Where x1 - x2 = 8 and the margin of error = 8

For the lower limit,

= 8 - 8 = 0

For the upper limit

= 8 + 8 = 16

Thus, CI = (0, 8)