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Rufina
15 days ago
5

On a fishing trip, you catch two fish . The weight of the first fish is shown (1.2lb). The second fish weighs at least 0.5 pound

more than the first fish. Write an inequality that represents the possible weights of the second fish
Mathematics
1 answer:
PIT_PIT [3.9K]15 days ago
7 0

Answer: 1.2 < 1.7x

Step-by-step explanation:

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A researcher is studying a group of field mice. the distribution of the weight of field mice is approximately normal with mean 2
AnnZ [3900]

Response:

b

Detailed explanation:

4 0
8 days ago
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−7x−50≤−1 AND−6x+70&gt;−2
PIT_PIT [3949]

Answer:

-7\geq x and [-7,12) expressed in interval notation.

Step-by-step explanation:

A compound inequality -7x-50\leq -1\text{ and }-6x+70>-2 has been provided. Our task is to determine the solution for this inequality.

Initially, we will address each inequality independently, followed by merging the findings by combining the overlapping intervals.

-7x-50\leq -1

-7x-50+50\leq -1+50

-7x\leq 49

By dividing with a negative number, it is necessary to reverse the inequality sign:

\frac{-7x}{-7}\geq \frac{49}{-7}

x\geq -7

-6x+70>-2

-6x+70-70>-2-70

-6x>-72

Again, dividing by a negative requires flipping the inequality sign:

\frac{-6x}{-6}

x

In combining both intervals, we will arrive at:

-7\geq x

Thus, the solution for the inequality provided is -7\geq x and [-7,12) in interval notation.

7 0
12 days ago
Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a
Inessa [3926]

Answer:

y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction

Explicación paso a paso:

La ecuación cuadrática que tenemos es (4y - 3)² = 72

Debemos encontrar el valor de y.

Ahora, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)

6 0
11 days ago
Read 2 more answers
give me 3 pictures showing the application of the sum and the product of the roots of quadratic equations in real life . describ
babunello [3666]

Quadratic equations find their application in various real-world scenarios such as: sports, bridges, projectile motion, the curvature of bananas, and so on.

Here are three images representing real-world instances of quadratics:

Example 1: A cyclist travels along a parabolic trajectory to leap over obstacles.

Example 2: A person throws a basketball towards the hoop, moving in a gently upward path described by a quadratic curve.

Example 3: A football player kicks the ball upward, which follows a quadratic path as it travels a distance.

4 0
4 days ago
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Based on daily measurements, Bob's weight has a mean of 200 pounds with a standard deviation of 16 pounds, while Mary's weight h
babunello [3666]

Answer:

(C) They have the same coefficient of variation

Step-by-step explanation:

The coefficient of variation (CV) is calculated using the formula:

CV = \frac{\sigma}{\mu}

Where \sigma represents standard deviation and \mu represents the mean.

Bob's average weight is 200 pounds with a standard deviation of 16 pounds

This indicates that \sigma = 16, \mu = 200.

Thus, his coefficient of variation is

CV = \frac{16}{200} = 0.08

Mary's average weight is 125 pounds, with a standard deviation of 10 pounds.

This implies \sigma = 10, \mu = 125

Therefore, her coefficient of variation is

CV = \frac{10}{125} = 0.08

Since both have the same coefficient of variation, the accurate response is.

(C) They have the same coefficient of variation

6 0
2 days ago
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