Answer:
(a1) The chance that the temperature rises by less than 20°C is 0.667.
(a2) The probability of the temperature increase falling between 20°C and 22°C is 0.133.
(b) The likelihood that the temperature increase could be hazardous at any moment is 0.467.
(c) The anticipated value of the temperature rise is 17.5°C.
Step-by-step explanation:
Let X denote the temperature increase.
The random variable X is distributed uniformly over the interval [10°C, 25°C].
The probability density function for X is shown here:
![f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.](https://tex.z-dn.net/?f=f%28X%29%3D%5Cleft%20%5C%7B%20%7B%7B%5Cfrac%7B1%7D%7B25-10%7D%3D%5Cfrac%7B1%7D%7B15%7D%3B%5C%20x%5Cin%20%5B10%2C%2025%5D%7D%20%5Catop%20%7B0%3B%5C%20otherwise%7D%7D%20%5Cright.)
(a1)
The probability of the temperature increase being under 20°C can be calculated as follows:

Consequently, the chance that the temperature increase will be below 20°C is 0.667.
(a2)
The probability of the temperature rise being in the range from 20°C to 22°C is computed as follows:

This leads to the probability of the temperature increase being between 20°C and 22°C being 0.133.
(b)
To find the probability that the increase in temperature could be dangerous, we calculate:
![P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467](https://tex.z-dn.net/?f=P%28X%3E18%29%3D%5Cint%5Climits%5E%7B25%7D_%7B18%7D%7B%5Cfrac%7B1%7D%7B15%7D%7D%5C%2C%20dx%5C%5C%3D%5Cfrac%7B1%7D%7B15%7D%5Cint%5Climits%5E%7B25%7D_%7B18%7D%7Bdx%7D%5C%2C%5C%5C%3D%5Cfrac%7B1%7D%7B15%7D%5Bx%5D%5E%7B25%7D_%7B18%7D%3D%5Cfrac%7B1%7D%7B15%7D%5B25-18%5D%3D%5Cfrac%7B7%7D%7B15%7D%5C%5C%3D0.467)
This results in a probability of 0.467 that the temperature rise is potentially dangerous at any time.
(c)
The expected value of the uniform random variable X is determined as follows:
![E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5](https://tex.z-dn.net/?f=E%28X%29%3D%5Cfrac%7B1%7D%7B2%7D%5B10%2B25%5D%3D%5Cfrac%7B35%7D%7B2%7D%3D17.5)
The expected value for the temperature increase computes to 17.5°C.