How many kilojoules of heat are required to heat 1.37kg of water from 21.3 to 89.5

The answer is A. Product molecules.

Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

• The ionic compound must exhibit neutrality; its total charge should equal zero.

• A binary ionic compound is formed from two distinct ions.

Ca²⁺ combines with either Br⁻ or S²⁻ to create binary ionic compounds.

• CaS is created when Ca²⁺ pairs with S²⁻ resulting in the neutral binary ionic compound CaS.

• CaBr₂ results from the combination of one mole of Ca²⁺ with two moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

V⁵⁺ can also unite with either Br⁻ or S²⁻ to produce binary ionic compounds.

• V₂S₅ is formed when two moles of V⁵⁺ bond with five moles of S²⁻ yielding the neutral binary ionic compound V₂S₅.

• VBr₅ is produced by combining one mole of V⁵⁺ with five moles of Br⁻ to form the neutral binary ionic compound VBr₅.

Thus, the empirical formulas for four binary ionic compounds that may be produced are: CaS, CaBr₂, VBr₅, and V₂S₅.

Answer:

There are 5.5668 moles of water for every mole of CuSO₄.

Explanation:

The mass of anhydrous CuSO₄ is:

23.403g - 22.652g = 0.751g.

mass of crucible + lid + CuSO₄ - mass of crucible + lid

Given that the molar mass of CuSO₄ is 159.609g/mol, we calculate the moles:

0.751g × = 4.7052x10⁻³ moles CuSO₄

The mass of water in the initial sample is:

23.875g - 0.751g - 22.652g = 0.472g.

mass of crucible + lid + CuSO₄ hydrate - CuSO₄ - mass of crucible + lid

As the molar mass of H₂O is 18.02g/mol, we find the moles:

0.472g × = 2.6193x10⁻² moles H₂O

The mole ratio of H₂O to CuSO₄ is:

2.6193x10⁻² moles H₂O / 4.7052x10⁻³ moles CuSO₄ = 5.5668

This indicates there are 5.5668 moles of water per mole of CuSO₄.

I hope this is helpful!

According to the Law, the variation in internal energy (U) of the system is equal to the total of the heat added to the system (q) plus the work performed ON the system (W)
<span>ΔU = q + W </span>

<span>In response to the first question, 0.653 kJ of heat energy is extracted from the system (balloon) while 386 J of work is applied to the balloon, leading to </span>
<span>ΔU = -653J + 386J </span>
<span>=-267J </span>
<span>Thus, the internal energy reduces by 267 J </span>

<span>For the second question, 322 J of heat is supplied to the system (gold bar) while no work is undertaken on the gold bar, marking this as an isochoric/isovolumetric process, thus </span>
<span>ΔU = 322J + 0 </span>
<span>=322J </span>
<span>Hence, internal energy rises by 322 J</span>

Answer:

0.605 molal

Explanation:

Molality indicates the solute amount in a specific solvent mass.

Let’s find the amount of benzene solute.

Mass of benzene = 13.3g

Molar mass of C6H6 = 12*6 +1*6 =72+7=78g/mol

Amount of benzene = mass/molar mass

                           =13.3/78

                          =0.1705mol

Molality = amount of solute/mass of solvent in kg

Mass of solvent = 282g = 0.282kg

Molality = 0.1705/0.282

    =0.605 molal