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Leto
5 days ago
14

If you weighed out 203 mg of the green chloro complex and dissolved it in 24.14 mL of acidic solvent, the molarity of your stock

solution would be 0.0295 M. Using your precise value of mass and volume that you entered above, please enter your calculated value for the concentration of the original green chloro complex stock solution in moles per liter.
Mgreen stock =
Chemistry
1 answer:
lions [2.7K]5 days ago
8 0

Answer:

The mass concentration is 0.00295 M

Explanation:

Mass Concentration = mass/volume

= 0.203 g/ 0.02414 L = 8.409 g/L

However, to find molarity we use the formula: Molarity = Mass concentration / molar mass

Thus, to describe Molar mass(mol/L) = mass concentration / molarity

=.84909 / 0.0295

= 285.06 g/mol

This means that 1 mol of green stock equals 285.06g

So, calculating for mol; 0.203 g corresponds to

= 0.00071213 g

= 0.00071213 g per 0.2414L = 0.0095 mol/L.

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The speed of light serves as the natural phenomenon that defines the meter's length. A meter is quantified as the distance light travels in a vacuum in 1/(299792458) seconds.

This definition is superior because using a standard meter stick can lead to inaccuracies due to variations in measurements resulting from different atmospheric conditions.

Explanation:

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1 month ago
Parker has a toy car he has made out of plastic building blocks. He breaks it apart so he can build something different with the
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C

Reasoning:

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9 days ago
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Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up
lions [2782]

Answer:

A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

According to the Second Law of Thermodynamics, not all energy produced when tires are incinerated can be effectively used due to losses associated with finite temperature differences. The energy obtainable from a tire when burned, measured in kilowatt-hours (E_{out}), can be calculated using the efficiency definition:

E_{out} = \eta \cdot E_{in}

Where:

\eta - Efficiency, which is dimensionless.

E_{in} - Energy released from burning, measured in kilowatt-hours.

Taking into account \eta = 0.5 and E_{in} = 75\,kWh, the yearly energy yield from a tire amounts to:

E_{out} = 0.5\cdot (75\,kWh)

E_{out} = 37.5\,kWh

Thus, the number of tires necessary to meet the electricity demand of ten homes for one year is:

n = \frac{(10\,homes)\cdot \left(10000\,\frac{kWh}{home} \right)}{37.5\,\frac{kWh}{tire} }

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A total of 2667 tires are necessary to satisfy the annual power needs of ten homes.

8 0
1 month ago
A chemist combined chloroform (CHCl3) and acetone (C3H6O) to create a solution where the mole fraction of chloroform is 0.187. T
KiRa [2857]

Answer:

\large \boxed{\text{c = 2.50 mol/L; b = 3.96 mol/kg }}

Explanation:

1. Molar concentration

Designate chloroform as C and acetone as A.

The molar concentration for C is derived from Moles of C per Litres of solution.

(a) Moles of C

We are assuming there are 0.187 moles of C.

This resolves that step.

(b) Litres of solution

Next, identify 0.813 moles of A.

(i) Mass of each component

\text{Mass of C} = \text{0.187 mol C} \times \dfrac{\text{119.38 g C}}{\text{1 mol C}} = \text{22.32 g C}\\\\\text{Mass of A} = \text{0.813 mol A} \times \dfrac{\text{58.08 g A}}{\text{1 mol A}} = \text{47.22 g A}

(ii) Volume of each component

\text{Vol. of C} = \text{22.32 g C} \times \dfrac{\text{1 mL C}}{\text{1.48 g C}} = \text{15.08 mL C}\\\\\text{Vol. of A} = \text{47.22 g A} \times \dfrac{\text{1 mL A}}{\text{0.791 g A}} = \text{59.70 mL A}

(iii) Volume of solution

Assuming mixing doesn't alter the total volume.

V = 15.08 mL + 59.70 mL = 74.78 mL

(c) Molar concentration of C

c = \dfrac{\text{0.187 mol}}{\text{0.07478 L}} = \textbf{2.50 mol/L }\\\\\text{ The molar concentration of chloroform is $\large \boxed{\textbf{2.50 mol/L}}$}

2. Molal concentration of C

Molal concentration is calculated as moles of solute per kilograms of solvent.

Total moles of C = 0.187 mol.

Mass of A = 47.22 g = 0.047 22 kg.

\text{b} = \dfrac{\text{0.187 mol}}{\text{0.047 22 kg}} = \textbf{3.96 mol/kg }\\\\\text{The molal concentration of chloroform is $\large \boxed{\textbf{3.96 mol/kg}}$}

4 0
1 month ago
The [H3O+] in a solution is increased to twice the original concentration. Which change could occur in the pH? 2.0 to 4.0 1.7 to
KiRa [2857]
Answer: second option: 1.70 to 1.40

Explanation:

1) pH is defined using the formula pH = - log [H₃O⁺]

2) Given that the initial concentration is x and after doubling it becomes 2x, we calculate:

pHi = - logx
pHf = - log 2x = - log 2 - logx

Thus, pHf - pHi = - log2 - logx - (- logx) = - log2 ≈ - 0.30

⇒ pHi - pHf = 0.30, indicating that the final pH (with twice the hydronium ions) is 0.30 lower than the starting pH.

3) The only option that indicates a 0.30 decline in pH is the second one: from 1.70 to 1.40. Therefore, that is the correct choice.


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1 month ago
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