All categories

2 months ago

Kennedy has a gross income of $95,000. What is her total tax due?

Mathematics

1 answer:

AnnZ [12.3K]2 months ago

3 0

Answer:

This brings her total gross income to $140,000 ($3,000 + $500 + $41,500 + $90,000 + $5,000), with her farm gross income being $95,000 ($90,000 + $5,000). Since 67.9% (which is at least two-thirds) of her gross income derives from farming ($95,000 ÷ $140,000 = .679), she qualifies for the special estimated tax rules designed for qualified farmers.

Step-by-step explanation:

You might be interested in

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th

Svet_ta [12734]

Answer:

$y>\frac{2}{3}x+3$

Step-by-step explanation:

Step 1

Calculate the slope of the dashed line

The slope between two points is computed with the formula:

$m=\frac{y2-y1}{x2-x1}$

We consider

(-3,1) and (0,3)

and substitute into it:

$m=\frac{3-1}{0+3}$

$m=\frac{2}{3}$

Step 2

Determine the equation of the dashed line in slope-intercept form:

$y=mx+b$

The equation we established is:

$m=\frac{2}{3}$

$b=3$ ---> associated problem

Substituting yields:

$y=\frac{2}{3}x+3$

Step 3

Establish the inequality corresponding to the graph

Given that it is represented by a dashed line, the area to the left of this line is shaded.

Thus,

$y>\frac{2}{3}x+3$

Refer to the attached diagram for enhanced understanding of the problem.

8 0

1 month ago

Read 2 more answers

For the month of June, Mae Green budgeted the following amounts: $180 for food, $475 for rent, $15 for transportation, $50 for i

tester [12383]

Question 1

Total budget sums up to 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990.
Actual expenditure amounts to 182 + 475 + 12 + 65 + 68 + 12.50 + 150 + 36 = $1000.5.

Mae Green surpassed her designated budget.

---------------------------------------------------------------------------------------------------------

Question 2

Eleanor:
Earned = 380.48
Spent = 16.50

Peter:
Earned = 120 + 13.65 + 100 = 233.65.

Combined total income = 233.65 + 380.48 - 16.50 = 597.63.

-------------------------------------------------------------------------------------------------------------

Question 3

Aggregate expenditure = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55.

-------------------------------------------------------------------------------------------------------------

Question 4

Marie's updated balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50.

------------------------------------------------------------------------------------------------------------

Question 5

[235/825] × 100 = 28.48%

4 1

1 month ago

Read 2 more answers

Lonzell said the function shown in the graph is positive on the interval (−,) and negative on the interval (−,−)open negative 5

Inessa [12570]

Answer:

The segments of the positive graph are located at the coordinates (-5,-4) and (2,5).

In contrast, the negative segment is identified as (-4,2).

Step-by-step explanation:

The positive graph is above the x-axis, while the negative portion lies beneath the y-axis.

Within the interval (-1,5),

The graph appears below the x-axis between (-1,2)

And above it between (2,5).

At this juncture, Lonzell’s assertion is inaccurate.

Within the interval (-5,-1),

The graph again resides below the x-axis in the range (-4,-1)

And above it between (-5,4).

At this point, Lonzell's assessment remains incorrect.

Thus,

The segments of the positive graph are at the coordinates (-5,-4) and (2,5).

Meanwhile, the negative segment is identified at (-4,2).

5 0

1 month ago

Find c1 and c2 such that M2+c1M+c2I2=0, where I2 is the identity 2×2 matrix and 0 is the zero matrix of appropriate dimension.

Inessa [12570]

The question lacks details. Below is the complete version provided.

Let M = $\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]$ . Find $c_{1}$ and $c_{2}$ such that $M^{2}+c_{1}M+c_{2}I_{2}=0$ , where $I_{2}$ is the identity 2x2 matrix and 0 is the zero matrix of the appropriate dimension.

Answer: $c_{1} = \frac{-16}{10}$

$c_{2}=\frac{-214}{10}$

Step-by-step explanation: The identity matrix is a square matrix with 1's along its main diagonal and 0's elsewhere. For example, a 2x2 identity matrix is:

$\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

$M^{2} = \left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]$

$M^{2}=\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]$

When solving the equation:

$\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+c_{1}\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right] +c_{2}\left[\begin{array}{cc}1&0\\0&1\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]$

The multiplication of a matrix by a scalar results in each term being scaled by that scalar. Matrices of different sizes cannot be combined.

So, we structure the equation as follows:

$\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+\left[\begin{array}{cc}6c_{1}&5c_{1}\\-1c_{1}&-4c_{1}\end{array}\right] +\left[\begin{array}{cc}c_{2}&0\\0&c_{2}\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]$