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LuckyWell
14 days ago
13

a speed limit of 100 kilometers per hour is approximately equal to 62 miles per hour. write an equation relating kilometers per

hour , k to miles per hour , m. then predict to following measures round to the nearest tenth.
Mathematics
2 answers:
Svet_ta [9.5K]14 days ago
8 0
The conversion between these units is 1 km/hr = 0.62 m/hr
PIT_PIT [9.1K]14 days ago
5 0

Answer:

m = 0.6k

Step-by-step explanation:

When an object has a speed of k kilometers per hour or m miles per hour, the relationship between k and m can be expressed as

\frac{m}{k}=c where c is a constant.

Substituting k = 100 km/hr and m = 62 mph allows us to figure out the value of c k.

\frac{62}{100}=c

c = 0.62 ≈ 0.6

This leads us to the equation \frac{m}{k}=0.6

Or m = 0.6k

1 kilometer per hour equals 0.6 miles per hour

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Question 1 Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your metho
babunello [8412]

Answer:

(a) The 95% confidence interval representing the percentage of the entire U.S. population that would select American football as their preferred television sport is (0.34, 0.40).

(b) Not reasonable.

Step-by-step explanation:

Given:

n = 1000

\hat p = 0.37

(a)

The confidence interval (1 - α)% for proportion p is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Where:

\hat p = the sample proportion

n = sample size

z_{\alpha/2} = critical z value.

Calculate the critical value of z for a 95% confidence level as shown:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Refer to a z-table for the necessary value.

Compute the 95% confidence interval for proportion p as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

=0.37\pm 1.96\times\sqrt{\frac{0.37(1-0.37)}{1000}}

=0.37\pm 0.03\\=(0.34, 0.40)

Thus, the 95% confidence interval indicating the proportion of individuals in the U.S. who might say their preferred sport on TV is American football is (0.34, 0.40).

(b)

Next, we must assess if it's rational to consider that the actual percent of people in the United States who favor American football on television is 33%.

The hypothesis is defined as:

H₀: The portion of the U.S. population claiming American football as their favorite sport on television is 33%, meaning p = 0.33.

Hₐ: The proportion of people in the U.S. whose favorite sport to watch on television is not 33%, or p ≠ 0.33

This hypothesis can be verified using a confidence interval.

The decision rule:

If the (1 - α)% confidence interval contains the null value of the hypothesis, then the null hypothesis is not rejected. If, however, the (1 - α)% confidence interval excludes the null value of the hypothesis, then the null hypothesis is rejected.

<pthe confidence="" interval="" for="" the="" proportion="" of="" all="" u.s.="" individuals="" indicating="" that="" american="" football="" is="" their="" favorite="" sport="" on="" television="">

The confidence interval does encompass the null value of p, which is 0.33.

<pthus the="" null="" hypothesis="" will="" be="" rejected.=""><pin conclusion="" it="" is="">not reasonable to accept that 33% represents the actual percentage of those in the U.S. whose favorite televised sport is American football.

</pin></pthus></pthe>
6 0
1 month ago
Shane and Abha earned a team badge that required their team to collect no less than 200020002000 cans for recycling. Abha collec
lawyer [9240]

Answer:

Shane must have gathered a minimum of 911 cans.

Step-by-step explanation:

Let S represent the number of cans Shane collected.

Since Abha collected 178 more cans, her total is S + 178.

The combined total should be at least 2000:

S + (S + 178) ≥ 2000

2S + 178 ≥ 2000

2S ≥ 2000 - 178

2S ≥ 1822

S ≥ 911

Therefore, Shane must have collected at least 911 cans.

8 0
1 month ago
Read 2 more answers
here are Xavier's bowling scores: 135, 140, 130, 190, 112, 200, 185, 172, 163, 151, 149 What is the mean?
PIT_PIT [9117]

Answer:

The average

Detailed breakdown:

the average is 157

7 0
10 days ago
In a study of hormone supplementation to enable oocyte retrieval for assisted reproduction, a team of researchers administered t
lawyer [9240]

Answer:

Please note: The provided question lacks completeness; the full question is below along with multiple choice options, and Option 3 is the right answer.

Step-by-step explanation:

Note: The question is incomplete, and presents several options.

1. The research team anticipates that 80% of comparable intervals will encompass the actual mean number of oocytes retrievable from the female population aged 36-40 years.

2. It is expected that 80% of similar intervals will cover the mean number of oocytes gathered from a sample of 98 women aged 36-40 years.

3. There is an 80% probability that the true average of retrievable oocytes from the 36-40 age group falls within the defined interval.

4. The expectation is that 80% of similarly constructed intervals will represent the possible range of oocytes that can be extracted from that demographic.

To select the proper option, we first need to clarify the concept of a confidence interval.

A Confidence Interval indicates the range where we can reasonably expect our true values to reside. In this scenario, the 80% confidence interval suggests that there is an 80% likelihood the actual values will reside within that interval. Let's compute it.

The data we possess from the question includes:

Sample Size = 98

Mean = 9.7

Confidence Level = 80%

Z Score = 1.282

The formula for the confidence interval is:

Mean ± Z x SD/\sqrt{n}

We have all variables except for SD, which is the standard deviation. First, we will determine that.

The standard deviation is derived from the square root of the variance, so we need to calculate the variance first.

Mean = Total/Sample Number

9.7 = Total/ 98

Total = 950.6

For calculating variance, we will utilize this total.

s² = (950.6 (1 - 9.7)²) ÷ (98-1)

s² = 741. 762 = Variance.

Now, let's find the Standard deviation

SD = \sqrt{variance}

SD = \sqrt{741.762}

SD = 27.23 = Standard Deviation.

Now we have all the necessary data for computing the 80% confidence interval range.

Mean ± Z x SD/\sqrt{n}

The Z-score, which we use is set for different confidence levels; in our case, for 80%, Z has a value of 1.282.

By inputting the numbers into the equation above, we can derive the range of values or the 80% confidence interval where our true value is likely to sit.

9.7 ± 1.282 x 27.23/\sqrt{98}

9.7 ± 3.52 Or

9.7 + 3.52 = 13.22

9.7 - 3.52 = 6.18

The Range of Values with 80% confidence interval = (6.18 to 13.22).

This indicates that our true mean is most likely found within this range.

Therefore, Option 3 is the accurate choice fulfilling the correct definition and context of the question.

6 0
17 days ago
This form will be sent to Lily by the end of January. She will use this W-2 form to...
Zina [9171]

Answer:

Lily must file her income taxes

Step-by-step explanation:

7 0
18 days ago
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