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Papessa
1 month ago
3

Translate and solve: 64 less than y is no less than −128.

Mathematics
2 answers:
tester [12.3K]1 month ago
8 0

In this scenario, we need to algebraically express the following:

"64 less than" y "is at least −128"

Thus:

64 less than y is represented as: y-64

At least −128 indicates that the term y-64 must be greater than or equal to -128.

<ptherefore reformulating="" the="" statement="" gives="" us:="">

y-64 \geq-128

Next, we solve:

y \geq-128 + 64\\y \geq-64

Answer:

y\geq-64

</ptherefore>
Leona [12.6K]1 month ago
5 0

Response:

y - 64 ≥ -128

y ≥ -64

Detailed solution:

Initial inequality:

y - 64 ≥ -128

Rearranging:

y - 64 + 64 ≥ -128 + 64

y ≥ -64

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Answer:

Indeed, having 15 people recognize the brand would be considered unusual, as it lies beyond 2 standard deviations from the average.

Step-by-step explanation:

Examine the provided data.

The average recognition rate for the Yummy brand name among groups is 12.5, with a standard deviation of 0.58.

Mean = μ= 12.5  

σ = 0.58

n = 15

\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]

Thus, having 15 people recognize the brand would indeed be unusual, as it is outside of the 2 standard deviations from the mean.

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The sum of two consecutive integers is one less than three times the smaller integer. Find the two integers
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4 0
26 days ago
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Which function has no horizontal asymptote? F (x) = StartFraction 2 x minus 1 Over 3 x squared EndFraction f (x) = StartFraction
tester [12383]

Response:

f(x)=\frac{2x^2}{3x-1}

Detailed explanation:

The function  f(x)=\frac{2x-1}{3x} features a horizontal asymptote which is y=\frac{2}{3}

The function  f(x)=\frac{x-1}{3x} presents a horizontal asymptote which is y=\frac{1}{3}

One function f(x)=\frac{2x^2}{3x-1} lacks a horizontal asymptote  because the degree of its numerator surpasses that of the denominator,

The function  f(x)=\frac{3x^2}{x^2-1} displays a horizontal asymptote which is y=3

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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
Leona [12618]

Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

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So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

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Again, cross-multiplying results in:

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Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

3 0
1 month ago
A nationwide survey of 100 boys and 50 girls in the first grade found that the daily average number of boys who are absent from
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sigma (difference)=√(sigma1/n1 + sigma2/n2). For this scenario:

sigma(d)= √(49/100 + 36/50)

Thus, the calculated standard deviation of the difference equals 1.1.

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1 month ago
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