Answer:
Hours
Step-by-step explanation:
This is an incorrect figure.
Answer:
Her age is 40 years
Step-by-step explanation:
Let Jerry's age be represented as j
Let Marjorie's age be denoted as m
The first part of the question states:
j = 4 + m/2
For the second equation:
m = 3j - 32
Multiply the first equation by 2 to get:
2j = 8 + m
Leading to m = 2j - 8
Set both equations for m equal to each other:
2j - 8 = 3j - 32
By simplifying, we get:
3j - 2j = 32 - 8
Therefore, j = 24
Now substituting back:
m = 2j - 8
m = 2(24) - 8
Thus, m = 48 - 8
Final result: m = 40
X^2 - x - 90 =0
This quadratic equation is in the standard format ax^2+ bx + c
The total of the solutions can be found using -b/a (where a and b are the coefficients from the original equation, not the solutions)
The resulting answer is 1/1 = 1
Answer:
7.
Detailed explanation:
28 can be expressed as 2^2 * 7.
In order to achieve a perfect square with 28, multiplying by 7 results in 2^2 * 7^2, equaling 14 squared.
Response:
![f(x)=4\sqrt[3]{16}^{2x}](https://tex.z-dn.net/?f=f%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D)
Detailed explanation:
You're likely in search of a function with a base that can be simplified to...
![4\sqrt[3]{4}\approx 6.3496](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B4%7D%5Capprox%206.3496)
The functions you seem to be considering appear to be...
![f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x](https://tex.z-dn.net/?f=f%28x%29%3D2%5Csqrt%5B3%5D%7B16%7D%5Ex%5Capprox%202%5Ccdot2.5198%5Ex%5C%5C%5C%5Cf%28x%29%3D2%5Csqrt%5B3%5D%7B64%7D%5Ex%3D2%5Ccdot%204%5Ex%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B16%7D%5E%7B2x%7D%5Capprox%204%5Ccdot%206.3496%5Ex%5C%20%5Cleftarrow%5Ctext%7B%20this%20one%7D%5C%5C%5C%5Cf%28x%29%3D4%5Csqrt%5B3%5D%7B64%7D%5E%7B2x%7D%3D4%5Ccdot%2016%5Ex)
It looks like the third option is the one that fits your requirements.