Answer:
3.4 x 10⁴ m/s
Explanation:
Analyze the circular path of the electron
B = magnetic field = 80 x 10⁻⁶ T
m = mass of an electron = 9.1 x 10⁻³¹ kg
v = speed in the radial direction
r = radius of the circular trajectory = 2 mm = 0.002 m
q = charge of an electron = 1.6 x 10⁻¹⁹ C
For the electron’s circular movement
qBr = mv
(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v
v = 2.8 x 10⁴ m/s
Now, consider the electron's movement in a straight line:
v' = speed in linear motion
x = distance traveled horizontally = 9 mm = 0.009 m
t = duration = 
= 
= 4.5 x 10⁻⁷ sec
Using the formula
x = v' t
0.009 = v' (4.5 x 10⁻⁷)
v' = 20000 m/s
v' = 2 x 10⁴ m/s
The resultant speed is given by
V = sqrt(v² + v'²)
V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)
v = 3.4 x 10⁴ m/s
Respuesta:
11.4 m/s
Explicación:
La fórmula para la aceleración centrípeta es:
donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.
En este problema,
a = g = aceleración debida a la gravedad en la cima = 
v = ?
R = 13.2 m
Por lo tanto,
v = 11.4 m/s
The moment the body impacts the ground, two types of Forces are produced: the gravitational pull and the Normal Force. This aligns with Newton's third law, indicating that every action has an equal and opposite reaction. If the downward force of gravity is directed toward the earth, the reactionary force from the block acts upwards, equivalent to its weight:
F = mg
Where,
m = mass
g = gravitational acceleration
F = 5*9.8
F = 49N
Consequently, the answer is E.
Answer:
a) The frequency is 3.191x10^11.
b) The type of radiation is microwave radiation.
c) The energy of one quantum of this radiation amounts to 1.32x10^-3ev.
Explanation:
For further details and calculations, please refer to the image below.
