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12345
10 days ago
9

A motorist enters a freeway at 45 km/h and accelerates uniformly to 99 km/h. From the odometer in the car, the motorist knows th

at she traveled 0.2 km while accelerating. Determine (a) the acceleration of the car, (b) the time required to reach 99 km/h
Physics
1 answer:
kicyunya [2.2K]10 days ago
5 0
a) 19440 km/h²; b) 10 seconds.
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Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your
inna [2210]

Answer:

The duration, t = 3.53 seconds

Explanation:

The following information is provided:

The equation to calculate the time t is expressed as:

t=(0.25)s^{1/2}...... (1)

Where

s denotes the distance in feet

We are to determine the duration taken by the stone to fall a distance of 200 feet, where s = 200 feet

Substituting the value of s into equation (1) yields:

t=(0.25)\times (200)^{1/2}

t = 3.53 seconds

Thus, the time taken by the object is 3.53 seconds, which provides the required answer.

4 0
25 days ago
A person weighing 55 kg walks by applying 160 N of force on the ground, while pushing a 10-kg object. If the person accelerates
Sav [2230]

Answer:

I'm uncertain

Explanation:

since I didn't provide a correct answer, continue with my inquiries and you can use 'I'm uncertain' for 100 points.

6 0
19 days ago
Mickey, a daredevil mouse of mass m , m, is attempting to become the world's first "mouse cannonball." He is loaded into a sprin
Ostrovityanka [2208]
The equations are h = v₀² / 2g, and h = k/4g x².
8 0
21 hour ago
Read 2 more answers
A solid metal sphere of diameter D is spinning in a gravity-free region of space with an angular velocity of ωi. The sphere is s
ValentinkaMS [2425]

Answer:

0.6

Explanation:

The formula for the volume of a sphere is \frac{4}{3} \pi (\frac{D}{2})^3

Thus \pi * r^2 * (\frac{D}{2} ) = \frac{4}{3} \pi (\frac{D}{2})^3

The radius of the disk is 1.15(\frac{ D}{2} )

Applying angular momentum conservation;

The M_i of the sphere = \frac{2}{5} m \frac{D}{2}^2

M_i of the disk = m*\frac{ \frac{1.15*D}{2}^2 }{2}

\frac{wd}{ws} = \frac{\frac{2}{5}m * \frac{D}{2}^2}{ m * \frac{(\frac{`.`5*D}{2})^2 }{2} }

= 0.6

5 0
25 days ago
slader A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of
serg [2593]

Response: 800N

Clarification:

Provided data:

Ball mass = 0.8kg

Contact duration = 0.05 seconds

Final and initial speed = 25m/s

The average force exerted by the ball on the wall can be calculated using the following relationship:

Force (F) = mass (m) * average acceleration (a)

a= (initial velocity (u) + final velocity (v))/t

m = 0.8kg

u = v = 25m/s

t = contact time of the ball = 0.05s

Thus,

a = (25 + 25) ÷ 0.05 = 1000m/s^2

Hence,

The average force magnitude (F)

F=ma

m = ball mass = 0.8

a = 1000m/s^2

F = 0.8 * 1000

F = 800N

6 0
15 days ago
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