Answer:
a-294
b-3.401×10^-6
c and d - 2.048×10^18
Explanation:
Multiply the RAM for each individual element by its molecular number, e.g., (c-12×14), and then sum to find the molar mass.
b-The molar mass is expressed in grams/mol, hence convert 1 mg to g, which equals 0.001, and divide it by the molar mass.
c/d-1 mole of any substance consists of 6.023×10^23 (ions, molecules, etc.), therefore we need to find the moles here as
(3.401×10^-6) × (6.023×10^23).
A flood that affects the environment where natural rubber is produced would severely hinder rubber production. In order to greatly limit production, a flood would need to destroy a significant portion of rubber trees. Natural rubber is crucial for manufacturing synthetic polymers. If the rubber supply is compromised (due to the disruption of its ecosystem caused by a flood), there would be a substantial decline in the availability of synthetic polymers.
hope this helps
Answer: The process of heating a crucible to eliminate moisture from a hydrate.
Explanation:
The available choices are:
a. Heating a solvent to aid in the dissolution of a solute.
b. Heating a solid in isolation to remove moisture.
c. Bringing water to a boil for use in a water bath.
d. Heating a crucible to eliminate moisture from a hydrate.
Possible actions that can be done on a hot plate include:
a. Heating a solvent to assist a solute in dissolving.
b. Heating a solid in isolation to dry it.
c. Heating water to boiling for a water bath.
However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.
Consequently, the correct procedure is heating a crucible to remove water from a hydrate.
In the reaction: <span>caco3(s) → cao(s) + co2(g), it is evident that
1 mol (which is 100 g) of CaCO3 yields 1 mol (which is 44 g) of CO2
Now, the molarity of CaCO3 present in the reaction system is
</span>=
=
= 0.45 mol
Thus, 0.45 mol of CaCO3 leads to the formation of 0.45 mol of CO2.
According to the ideal gas equation, we have PV = nRT
V =
.
Considering P = 645 torr = 0.8487 atm (because 1 atm = 760 torr)
In that case, V =
= 34.8 l
