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26 days ago

What is the ratio of Srmc004-1.jpg ions to Brmc004-2.jpg ions in a neutral compound? 1:1 1:2 2:1 3:2

Chemistry

2 answers:

Anarel [2.6K]26 days ago

4 0

Answer:

1:2

Explanation:

I just completed it.

lorasvet [2.5K]26 days ago

4 0

Strontium (Sr) is located in the second group of the periodic table, indicating it possesses two electrons in its valence shell, leading to the formation of the Sr⁺² ion. In contrast, bromine (Br) contains seven valence electrons, resulting in the creation of the Br⁻ ion. Thus, a single strontium atom can donate electrons to two bromine atoms. Consequently, the ratio of ions in neutral strontium bromate (SrBr₂) is 1:2.

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A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d

lorasvet [2529]

Answer:

The original halide's formula is SrCl₂.

Explanation:

The chemistry reaction's balanced equation is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.

Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.

The moles of SrSO₄ (n = mass/molar mass) = (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.

The moles of SrX can thus be calculated as 4.11 x 10⁻³ moles based on stoichiometry from the balanced equation.

n = mass / molar mass, thus n = 4.11 x 10⁻³ moles and mass = 0.652 g.

The molar mass of SrX₂ is calculated using mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.

The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).

Calculating the atomic mass of halide X, we find = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2 g/mole = 35.5 g/mole.

This identifies the atomic mass of Cl.

Consequently, the original halide's formula is SrCl₂.

4 0

27 days ago

Modern commercial airliners are largely made of aluminum, a light and strong metal. But the fact that aluminum is cheap enough t

lorasvet [2529]

Respuesta:

Un avión fabricado con aluminio puede transportar una mayor cantidad de pasajeros comparado con uno de acero.

Explicación:

La masa total que el avión es capaz de levantar es:

$m_{tot}=m_{fuselage}+m_{passangers}$

Para el aluminio:

$m_{tot}=m_{fus-Al}+m_{pas-Al}$

$m_{fus-Al}=\delta _{Al}*V_{fuselage}$

$V_{fuselage}=\frac{\pi *L}{4}*[D^2-(D-e)^2]$

donde:

L es longitud
D es diámetro
e es grosor

$m_{tot}=\delta _{Al}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Al}$

Para el acero (mismo procedimiento):

$m_{tot}=\delta _{Steel}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Steel$

Sabiendo que la masa total que el avión puede levantar es constante y que el aluminio tiene una densidad menor que la del acero, podemos afirmar que el avión de aluminio puede levantar un mayor número de pasajeros.

También es posible estimar un peso promedio de los pasajeros para calcular cuántos podría soportar.

5 0

1 month ago

(a) calculate the %ic of the interatomic bond for the intermetallic compound tial3. (b) on the basis of this result, what type o

Tems11 [2400]

Answer :

The percentage ionic character (%IC) equals 10%, indicating the bond is mostly covalent with slight polarity.

Percent Ionic Character:

This reflects the fraction of ionic nature within a polar covalent bond. The formula for %IC (% ionic character) is:

$Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^X^a^-^X^b^) * 100$