Response:
Clarification:
Hello,
In this scenario, since a single drop equates to 0.05 mL of the solution provided, with a concentration of 0.02 g/mL, the mass of oleic acid in one drop calculates to:
Best wishes.
Answer:
Indeed, the chemist is capable of identifying the compound present in the sample.
Explanation:
In one mole of K₂O, potassium has a mass of 2 × 39.1 g = 78.2 g, while the total mass of K₂O is 94.2 g. The mass ratio of K compared to K₂O is calculated as 78.2 g / 94.2 g = 0.830.
For 1 mole of K₂O₂, potassium's mass remains the same at 78.2 g, but the total mass of K₂O₂ is 110.2 g. The mass ratio of K to K₂O₂ then equates to 78.2 g / 110.2 g = 0.710.
When the chemist measures the mass of K in relation to the overall sample, the mass ratio can be computed.
- If the mass ratio is 0.830, then it indicates a pure K₂O compound.
- If the mass ratio is 0.710, it indicates a pure K₂O₂ compound.
- If the mass ratio falls outside of 0.830 or 0.710, the sample is assessed to be a mixture.
Greetings!
The result is:
The new volume is: 
Rationale:
Because the temperature remains constant, we can apply Boyle's Law to solve this issue.
Boyle's Law stipulates that:
Where,
P is the gas's pressure.
V is the gas's volume.
According to the information provided:
Let's put the values into the equation:
Consequently, the new volume is:
Wishing you a lovely day!
Answer:
0.5 g/mL----- will float
1.0 g/mL---- will float
2.0 g/mL----- will sink
Explanation:
Objects with a density less than or equal to that of water will float due to having a lower mass, while objects with a density exceeding that of water will sink because their mass is greater than that of water. Thus, objects with a density of 0.5 g/mL and 1.0 g/mL will float since they are less dense than water (1 g/mL), whereas an object with a density of 2.0 g/mL will sink.
Answer:
The force is 38503.5N.
Explanation:
From the problem, we determine:
P (pressure) = 5.00 atm.
Next, to find the force in Newtons (N), we must convert 5 atm into N/m², as shown:
1 atm equals 101325 N/m².
So, 5 atm equals 5 x 101325 = 506625 N/m².
A (the piston area) = 0.0760 m².
Pressure signifies force per unit area, mathematically represented as
P = F/A.
From this, we find F = P × A.
F = 506625 × 0.0760.
Therefore, F = 38503.5N.
Thus, the piston experiences a force of 38503.5N.
