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PSYCHO15rus
3 months ago
10

An insulin drip is mixed as 500.0 units in 250.0 mL Normal Saline (NS). Calculate the drip rate in mL/h needed to deliver 4.0 un

its/h?
Chemistry
1 answer:
Alekssandra [3K]3 months ago
3 0

Answer:

Drip rate = 2 ml/h

Explanation:

Given:

Total insulin = 500 units

Volume of saline = 250 ml

Desired infusion rate = 4.0 units/h

Find:

Drip rate

Calculation:

Concentration = Units of insulin / Volume of saline

= 500 / 250

Concentration = 2 units/ml

Drip rate = Infusion rate / concentration

Drip rate = 4 / 2

Drip rate = 2 ml/h

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Answer:

The result is "4,241.17 years"

Explanation:

The disintegration rate for C-14 atoms is indicated in  15.3 \frac{atoms}{min-g}

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The C-14 proportion within the sample can be determined as per = \frac {9.16}{15.3} \\\\ = 0.5987

With a half-life of 5730 years.

Now, we need to compute the number of half-lives (n) that are applicable:

(\frac{1}{2})^n= A\\\\A= fraction of C-14, which is remaining \\\\(\frac{1}{2})^n= 0.5987 \\\\ n \log 2 = - \log 0.5987\\\\

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Thus, the age of the sample is represented as = n \times\ half-life

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Barbiturates, including "truth serums" seen in movies like Meet the Fockers and sedatives that may have led to the untimely deat
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Answer:

Explanation:

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3 months ago
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