Answer:
Angle ABE measures 27°.
Explanation:
Refer to the attached diagram related to this question.
The given values are ∠ABE=2n+7 and ∠EBF=4n-13.
Clearly seen in the diagram, ∠ABE and ∠EBF are equal in measure.
Move variable components to one side of the equation.
Split both sides by 2.
The solution for n arrives at 10.
The next step is to calculate ∠ABE.
Consequently, the measurement of angle ABE is 27°.
A compound signifies a substance comprised of two or more elements that have undergone a chemical combination. A polyatomic ion, often referred to as a molecular ion, represents a charged particle formed from two or more atoms. An example would be the nitrate ion (NO3-), which consists of one nitrogen atom and three oxygen atoms covalently bonded, acting as a single charged entity. Thus, the apt term would be a polyatomic ion or a molecular ion.
Answer: Rearrange the lone pairs of electrons from the outer atom(s) to create double or triple bonds with the central atom.
Explanation:
Answer:
Mitochondria are plentiful in mammalian cells, with their proportions varying across different tissues, from less than 1% in white blood cells to as high as 35% in heart muscle cells. It is essential to understand that mitochondria are not static structures but instead form a dynamic network that frequently undergoes processes of fission and fusion. In skeletal muscle, they exist as part of a reticular membrane network. The two subpopulations, subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria, occupy different subcellular regions and exhibit slight differences in their biochemical and functional characteristics tied to their anatomical context. The SS mitochondria are positioned just beneath the sarcolemma, while IMF mitochondria are found closely associated with myofibrils. Their distinct properties likely play a role in their adaptability. SS mitochondria make up about 10-15% of the total mitochondrial volume and are believed to be more adaptable than their IMF counterparts, despite the latter displaying higher levels of protein synthesis, enzyme activity, and respiration (1).
Explanation:
According to the Law, the variation in internal energy (U) of the system is equal to the total of the heat added to the system (q) plus the work performed ON the system (W)
<span>ΔU = q + W </span>
<span>In response to the first question, 0.653 kJ of heat energy is extracted from the system (balloon) while 386 J of work is applied to the balloon, leading to </span>
<span>ΔU = -653J + 386J </span>
<span>=-267J </span>
<span>Thus, the internal energy reduces by 267 J </span>
<span>For the second question, 322 J of heat is supplied to the system (gold bar) while no work is undertaken on the gold bar, marking this as an isochoric/isovolumetric process, thus </span>
<span>ΔU = 322J + 0 </span>
<span>=322J </span>
<span>Hence, internal energy rises by 322 J</span>
