What volume of co2 gas at 645 torr and 800. k could be produced by the decomposition of 45.0 g of caco3? caco3(s) → cao(s) + co2

Response:

q < 0, w > 0, the sign of ΔE cannot be ascertained from the provided details

Explanation:

Assessing the sign of q

The water bath's temperature before the reaction is at 25 °C

Following the reaction, the water bath's temperature rises to 28 °C, suggesting that heat was released from the system during the reaction.

If heat is absorbed by the system, q is positive; if heat is released, q is negative, leading to the conclusion that q < 0 in this scenario.

Determining the sign of w

The downward movement of the piston indicates a reduction in the system's volume, meaning work was conducted on the system. When work is done on the system, w is considered positive; hence, w > 0 in this case.

Evaluating ΔE sign

According to the first law of thermodynamics, the relationship among ΔE, q, and w is represented as follows:

ΔE = q + w

In this instance, since q is negative and w is positive, the resulting sign of ΔE is determined by the relative magnitudes of q and w. Since we lack sufficient information to gauge these magnitudes, we cannot definitively determine the sign of ΔE based on the given data.

As a result, the correct option among the choices presented is c: q < 0, w > 0, the sign of ΔE cannot be discerned from the information given.

The element with atomic number 58 is Cerium, meaning its symbol should be Ce rather than Co, which belongs to Cobalt with atomic number 27. Therefore, the notation for isotopes consists of the element's symbol accompanied by a superscript and a subscript, properly aligned. The superscript indicates the mass number.

Mass number = protons + neutrons = 58 + 33 = 91

The subscript denotes the atomic number, which is 58. This notation is illustrated in the attached image.

Answer:

The dependent variable in this experiment is the egg's position above the water.

Explanation:

The dependent variable refers to the factor that is influenced by another variable.

On the other hand, the independent variable is what can be altered, affecting the dependent variable's outcome.

The controlled variable remains constant throughout the experiment.

In this setup, the amount of salt added acts as the independent variable, while the flotation level of the egg is the dependent variable, and the water volume in each cup represents the controlled variable.

Answer:

Step 1:

N

H

+

3

C

H

2

C

H

2

N

H

+

3

(

a

q

)

⇌

A.

K

a

1

B.

K

a

2

C.

K

b

1

D.

K

b

2

Step 2:

N

H

2

C

H

2

C

H

2

N

H

+

3

(

a

q

)

⇌

A.

K

a

1

B.

K

a

2

C.

K

b

1

D.

K

b

2

Acid-

Response:

The conclusion to your inquiry is Pressure 1 = 1.73 atm

Clarification:

Data provided

Volume 1 = 5 l

Pressure 1 =?

Volume 2 = 12 l

Pressure 2 = 0.72 atm

Procedure

To resolve this issue, Boyle's law is applied

                 Pressure 1 x Volume 1 = Pressure 2 x Volume 2

-Finding Pressure 1

                 Pressure 1 = Pressure 2 x Volume 2 / Volume 1

-Replace values

                 Pressure 1 = 0.72 x 12 / 5

-Calculating

                Pressure 1 = 8.64/5

-Final outcome

                 Pressure 1 = 1.73 atm