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Ilia_Sergeevich
15 days ago
7

A model that describes the population of a fishery in which harvesting takes place at a constant rate is given by dP dt = kP − h

, where k and h are positive constants. (a) Solve the DE subject to P(0) = P0. P(t) = (b) Describe the behavior of the population P(t) for increasing time in the three cases P0 > h/k, P0 = h/k, and 0 < P0 < h/k. P0 > h/k P(t) decreases as t increases P(t) increases as t increases P(t) = 0 for every t P(t) = P0 for every t P0 = h/k P(t) decreases as t increases P(t) increases as t increases P(t) = 0 for every t P(t) = P0 for every t 0 < P0 < h/k P(t) decreases as t increases P(t) increases as t increases P(t) = 0 for every t P(t) = P0 for every t (c) Use the results from part (b) to determine whether the fish population will ever go extinct in finite time, that is, whether there exists a time T > 0 such that P(T) = 0. If the population goes extinct, then find T. (If the population does not go extinct, enter DNE.)
Mathematics
1 answer:
lawyer [4K]15 days ago
8 0

It grows at T because the behavior has accelerated

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Answer: 0.46

Step-by-step explanation:

B&B Motors' mini trucks yield 0.59; all four companies combined yield 0.39; mini trucks yield 0.13. Hence, 0.59 - 0.13 equals 0.46.

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Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif
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To simplify the expression:
-(6 x^3 - 2 x + 3) - 3 x^3 + 5 x^2 + 4 x - 7

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Combine 4 x and 2 x to get 6 x:
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Jada intends to provide milk and nutritious cookies at a gathering for her book club. She has planned to offer 12 ounces of milk and 4 cookies for each participant. With her included, the total number of club members is 15. Each package of cookies has 24 cookies and is priced at $4.50. A gallon of milk has 128 ounces and costs $3. Let n denote the club members, m for the ounces of milk, c for the cookies, and b for Jada's budget in dollars. Identify all equations that could represent the relevant quantities and constraints in this scenario.

â m = 12(15)

n refers to the club members

b. 3m + 4.5c = 6

c. 4n =

m stands for ounces of milk

& 44.50) = C

c indicates the cookies

e b=2(3) + 3(4.50)

b denotes Jada's budget in

currency

The equations applicable for representing the quantities and constraints in this scenario are:

a) m = 12(15)

c)4n = c

e) b = 2(3) + 3(4.50)

Detailed explanation:

Jada is set to provide milk and nutritious cookies for her book club meeting

She plans to prepare 12 ounces of milk and 4 cookies for each individual

She has 15 members in total

A pack of cookies contains 24 cookies and costs $4.50

A gallon of milk has 128 ounces and costs $3

Designate the total members by n

Ounces of milk = m

The number of cookies = c

Jada's budget in dollars = d

y = 12(15)

Each individual will receive 4 cookies

4n = c

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She requires = 15 × 4 = 60 cookies

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A gallon of milk contains 128 ounces

180 ÷ 128 = 1.406

She will need to acquire 2 gallons of milk

It's noted: from the prompt

Each gallon of milk costs $3

Each package of cookies costs $4.50

b serves as Jada's dollar budget

b = 2(3) + 3(4.50)

<pThe relevant equations that could signify the quantities and constraints in this scenario are:

Options a, c and e are valid

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Step-by-step explanation:

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Dividing both sides by 0.5:

x = (3.6 * 7.5) / 0.5

x = 54

So, you assisted 54 customers in 7.5 hours.

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14 days ago
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