All categories

1 day ago

Why did the cow give only buttermilk

1 answer:

5 0

The query arises from an activity that must be completed to acquire the letters filling in the answer. After participation in this activity, the response to why the cow provided only buttermilk is "What else can she provide but her milk." The phrase "But-her-milk" is a play on words with "buttermilk." I hope this clarification assists you.

You might be interested in

Kevin drew a triangle with angle measures of 30 degrees and 40 degrees and side measures of 5 cm, 7cm, and 8 cm. Explain, using

lawyer [9226]

He created a scalene triangle.
A scalene triangle has sides and angles that do not measure alike.

6 0

25 days ago

Read 2 more answers

Question 1 Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your metho

babunello [8402]

Answer:

(a) The 95% confidence interval representing the percentage of the entire U.S. population that would select American football as their preferred television sport is (0.34, 0.40).

(b) Not reasonable.

Step-by-step explanation:

Given:

n = 1000

$\hat p$ = 0.37

(a)

The confidence interval (1 - α)% for proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Where:

$\hat p$ = the sample proportion

n = sample size

$z_{\alpha/2}$ = critical z value.

Calculate the critical value of z for a 95% confidence level as shown:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Refer to a z-table for the necessary value.

Compute the 95% confidence interval for proportion p as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.37\pm 1.96\times\sqrt{\frac{0.37(1-0.37)}{1000}}$

$=0.37\pm 0.03\\=(0.34, 0.40)$

Thus, the 95% confidence interval indicating the proportion of individuals in the U.S. who might say their preferred sport on TV is American football is (0.34, 0.40).

(b)

Next, we must assess if it's rational to consider that the actual percent of people in the United States who favor American football on television is 33%.

The hypothesis is defined as:

H₀: The portion of the U.S. population claiming American football as their favorite sport on television is 33%, meaning p = 0.33.

Hₐ: The proportion of people in the U.S. whose favorite sport to watch on television is not 33%, or p ≠ 0.33

This hypothesis can be verified using a confidence interval.

The decision rule:

If the (1 - α)% confidence interval contains the null value of the hypothesis, then the null hypothesis is not rejected. If, however, the (1 - α)% confidence interval excludes the null value of the hypothesis, then the null hypothesis is rejected.

The confidence interval does encompass the null value of p, which is 0.33.

<pthus the="" null="" hypothesis="" will="" be="" rejected.=""><pin conclusion="" it="" is="">not reasonable to accept that 33% represents the actual percentage of those in the U.S. whose favorite televised sport is American football.

</pin></pthus></pthe>

6 0

1 month ago

The mass of a colony of bacteria, in grams, is modeled by the function P given by P(t)=2+5tan^−1.(t/2), where t is measured in d

AnnZ [9071]

Answer:

1.21 g/day

Step-by-step explanation:

We start with the fact that

The mass of the bacterial colony (in grams) is described by

$P(t)=2+5tan^{-1}(\frac{t}{2})$

Where t=Time(in days)

Next, we differentiate with respect to t

$P'(t)=5(\frac{1}{1+\frac{t^2}{4}}\times \frac{1}{2})$

Using the formula $\frac{d(tan^{-1}(x)}{dx}=\frac{1}{1+x^2}$

$P'(t)=\frac{5}{2}(\frac{4}{4+t^2})$

$P'(t)=\frac{10}{4+t^2}$

We know that P(t)=6

Now, substitute this value

$6=2+5tan^{-1}(\frac{t}{2})$

$5tan^{-1}(\frac{t}{2})=6-2=4$

$tan^}{-1}(\frac{t}{2})=\frac{4}{5}$

$\frac{t}{2}=tan(\frac{4}{5})$

$t=2tan(\frac{4}{5})$

Insert the given value of t

$P'(2tan\frac{4}{5})=\frac{10}{4+4tan^2(\frac{4}{5})}$

$P'(2tan\frac{4}{5})=\frac{10}{4}\times \frac{1}{1+tan^2(\frac{4}{5})}$

We understand that $1+tan^2\theta=sec^2\theta$

Applying the formula

$P'(2tan(\frac{4}{5})=\frac{5}{2}\times \frac{1}{sec^2(\frac{4}{5})}$

$P'(2tan\frac{4}{5})=\frac{5}{2}\times cos^2(\frac{4}{5})$

By employing $cos^2x=\frac{1}{sec^2x}$

$P'(2tan\frac{4}{5})=\frac{5}{2}\times (0.696)^2=1.21$ g/day

Consequently, the instantaneous rate at which the mass of the colony changes is=1.21g/day

7 0

1 month ago

Read 2 more answers

An athlete jumped 5.5 feet which was 1.1 times higher than the previous jumper how high did the previous athlete jump

Svet_ta [9486]

Answer:

5 ft

Step-by-step explanation:

Denote the height of the previous jump as j. Therefore, it follows that 1.1j equals 5.5 ft.

By dividing both sides by 1.1, we derive j = 5 ft. This indicates the height from the prior jump.

3 0

29 days ago

Read 2 more answers

3. Atile warehouse has Inventory at hand and can put in for a

tester [8808]

Detailed explanation:

According to the equation that defines this order as;

The number of tiles = 12b + 38 where;

b signifies the quantity of bundles ordered.

To find out how many bundles are needed if a customer requires 150 tiles, substitute the number of tiles into the established equation to determine the value of b. This process is outlined below;

By substituting;

150 = 12b + 38

12b = 150 - 38

12b = 112

b = 112/12

b = 9.33

b ≈ 9 bundles

It is important to round this figure up because the quantity of tiles must be whole numbers.

5 0

1 month ago