Option (C.) is the right choice!
It's about constructing the perpendicular bisector..!!!
Answer:
B. (x + 16) + (6x − 4) = 180
Step-by-step explanation:
The Theorem of Cyclic Quadrilaterals states that in any quadrilateral located within a circle, the angles opposite to each other will sum to 180 degrees. Therefore, the conclusion can be drawn:
∠A + ∠C = 180° leading to (x + 16) + (6x - 4) = 180°
∠B + ∠D = 180° which equates to x + (2x - 16) = 180°
The reason is rooted in the angle addition postulate. If we have the scenario where TR is a line intersecting segment VS at point R, we can establish that by applying the angle addition postulate, we can deduce that x is equal to 30. In option (1), which uses the substitution property of equality, this condition cannot be utilized correctly here. Option (3) involving the subtraction property of equality does not apply either. Lastly, option (4) regarding the addition property of equality is also inappropriate for deriving the value of x.
Lengthwise count of 1/2-inch cubes = 8 1/2 ÷ 1/2 = 17
Widthwise count of 1/2-inch cubes = 5 1/2 ÷ 1/2 = 11
Heightwise count of 1/2-inch cubes = 2 1/2 ÷ 1/2 = 5
Total number of 1/2-inch cubes = 17 x 11 x 5 = 935
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Answer: 935 1/2-inch cubes are required.
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Question
Consider this system of equations. Which shows the second equation written in slope-intercept form?
A. 
B. 
C. 
D. 
Response:
B.
Detailed explanation:
Given
Equation 1:
Equation 2:
Required:
Equivalent of equation 2
To achieve an equivalence of equation 2 (in slope-intercept form), we must first simplify it
Open the brackets
Simplify the fractions
Divide by 2
Re-arrange
Next, we compare options A through D with
A. is not equal to
Next, we check the second option
B.
matches
This option represents the second equation in slope-intercept format.
We check for further options
C.
Convert the fraction into a decimal
This does not equal
D.
Convert the fraction to decimal
This also does not equal to
Therefore, the only option equivalent to the second equation in slope-intercept form is Option B
