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29 days ago

What is the molarity of potassium ions in a 0.122 M K2CrO4 solution

Chemistry

2 answers:

eduard [2.5K]29 days ago

6 0

The concentration of potassium ions in a K2CrO4 solution that is 0.122 M is 0.244 M.

Explanation

To derive the dissociation reaction for K2CrO4, we have:

K2CrO4 (aq) → 2K^+ (aq) + CrO4^2- (aq)

K2CrO4 dissociates to yield 2 potassium ions, thus the concentration of potassium ions = 2 x 0.122 = 0.244 M.

eduard [2.5K]29 days ago

4 0

Answer: The concentration of potassium ions in a $K_2CrO_4$ solution is 0.244 M

Explanation:

The dissociation reaction of $K_2CrO_4$ in solution is as follows:

$K_2CrO_4\rightarrow 2K^++CrO_4^{2-}$

From this reaction, we find that one mole of $K_2CrO_4$ dissociates in solution to form 2 moles of $K^+$ (potassium ion) and 1 mole of $CrO_4^{2-}$ (chromate ion).

According to the question,

0.122 M of $K_2CrO_4$ dissociates in solution resulting in $2\times 0.122M=0.244M$ of $K^+$ (potassium ion) and 0.122 M of $CrO_4^{2-}$ (chromate ion).

Therefore, the concentration of potassium ions in a $K_2CrO_4$ solution is 0.244 M

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