E = mc²
where E = energy produced
m = mass of the nucleus
C = speed of light
m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg
C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶
E = 1.37 x 10⁻¹² J
Answer:
3.816 × 10⁻³ M
Explanation:
A stock solution of Cu²⁺(aq) is made by dissolving 0.8875 g of solid Cu(NO₃)₂∙2.5H₂O in a 100.0-mL volumetric flask, and then brought up to volume with water. What is the molarity (in M) of Cu²⁺(aq) in this stock solution?
We can derive the following relations:
- The molar mass of Cu(NO₃)₂∙2.5H₂O is 232.59 g/mol.
- Each mole of Cu(NO₃)₂∙2.5H₂O yields one mole of Cu²⁺.
The moles of Cu²⁺ present in 0.8875 g of Cu(NO₃)₂∙2.5H₂O are:

The molarity of Cu²⁺ is:

Answer:
Oversight of weights and measures ensures correct evaluations of goods and services so that everyone receives a fair exchange in the marketplace. It also acts as a deterrent, promoting honesty among traders.
Explanation:
Answer:
0.605 molal
Explanation:
Molality indicates the solute amount in a specific solvent mass.
Let’s find the amount of benzene solute.
Mass of benzene = 13.3g
Molar mass of C6H6 = 12*6 +1*6 =72+7=78g/mol
Amount of benzene = mass/molar mass
=13.3/78
=0.1705mol
Molality = amount of solute/mass of solvent in kg
Mass of solvent = 282g = 0.282kg
Molality = 0.1705/0.282
=0.605 molal
A. iodine C. fluorine F. bromine Explanation: Ionic bonds primarily form between metals and non-metals, typically where there exists a significant difference in electronegativity between the constituent atoms. This situation results in one atom seeking to gain electrons while the other donates them. For zinc to form a compound in a 1:2 ratio, its combining power must align accordingly. The prevalent oxidation state of zinc is +2. The other combining atoms must also possess the capacity to accept two electrons. The halogens fit perfectly here, as they require only one electron to achieve stability and are highly electronegative. Hence, if two halogens combine with zinc, they will result in an ionic bond. The relevant halogens include fluorine, chlorine, bromine, iodine, and astatine which will yield compounds: ZnF₂, ZnBr₂, and ZnI₂.