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Aleksandr-060686
2 months ago
15

. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it

. (a) What is the force constant of the spring? (b) What is the unloaded length of the spring?
Physics
1 answer:
serg [3.5K]2 months ago
3 0

Answer:

29.4 N/m

0.1

Explanation:

a) The restoring force is described by: F_r = -k*x.

The gravitational force is given as: F_g = mg.

Where:

F_r = restoring force,

F_g = gravitational force,

g represents acceleration due to gravity,

and k is the force constant, while x1 and x2 are the displacements for the two masses.

Given:

m1 = 1.29 kg,

m2 = 0.3 kg,

x1 = -0.75 m,

x2 = -0.2 m,

g = 9.8 m/s².

Substituting the information yields:

F_r = F_g

-k*x1 + k*x2 = m1*g - m2*g.

Solving gives k = 29.4 N/m.

b) To find the unloaded length l:

l = x1 - (F_1/k).

Given:

m1 = 1.95kg, x1 = -0.75m.

Substituting in provides:

l = x1 - (F_1/k) = 0.1.

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