A wind turbine works by slowing the air that passes its blades and converting much of the extracted kinetic energy to electric e

To start, we first need to determine the kinetic energy of the penny before it strikes the ground. This is calculated using the formula where m equals 5.25 g, which is 0.00525 kg for the penny's mass, and v equals 3.27 m/s for its speed. Replacing the values into the equation provides: When the penny lands, all this kinetic energy transforms into internal energy for both the penny and the ground. If half of this energy goes into the penny's internal energy, the change is determined by a specific formula where m is the penny's mass, Cs is its specific heat capacity (2.03 J/gC), and , the change in temperature. To find the last element, the equation will be solved.

The male skater reaches a velocity of 13.71 m/s. According to the principle of conservation of momentum, m1u1 = (m1 + m2)u2, where m1 signifies the mass of the male skater at 78.2 kg, m2 is the mass of the female partner at 48.5 kg, u1 is the male skater's resulting velocity from the push, and u2 is the velocity imparted to the female skater, which was 8.46 m/s. Through the formula, we find u1 = [(78.2 + 48.5) × 8.46] ÷ 78.2, which calculates to 1071.882 ÷ 78.2 resulting in u1 = 13.71 m/s.

Answer:The tension on either side of the cable is 3677.57 N

Explanation:

given data

traffic light = 20 kg

cable spanning between two poles = 30 m

sag of the cable = 0.40 m

solution

through the free body diagram

tan θ = .............1

θ = 1.527 °

and

tension = mg

The horizontal net force can be stated as

T2 cosθ = T1 cosθ.................2

and

thus T2 - T1..............3

and

in the vertical axis we express as

( T1 + T2) sinθ = mg...................4

therefore using equation 3 here

2 × T1 sin(1.527) = 20 × 9.8

T1 = 3677.57 N

Complete Question:

Picture yourself on an aluminum ladder on the ground, attempting to fix an electrical connection with a metal screwdriver featuring a metallic handle. Since you are sweating profusely, your body has a resistance of 1.60 kΩ.

(a) If you accidentally contact the "hot" wire from the 120 V power line, what current will flow through your body?

(b) What is the amount of electrical power transferred to your body?

Answer:

(a) 0.075A

(b) 9W

Explanation:

According to Ohm's law, the voltage (V) applied to or passing through a body corresponds to the current (I) via the relationship:

V ∝ I

=> V = I x R                 ----------------------(i)

Where;

R denotes the resistance of the body

(a) As mentioned;

Due to wet conditions, the body will conduct electricity, and possesses the following values;

V = supplied voltage = 120V

R = resistance of the wet body = 1.60kΩ = 1.6 x 1000Ω = 1600Ω

Substituting these values into equation(i):

120 = I x 1600

To find I;

I =

I = 0.075A

Thus the current passing through your body is 0.075A

(b) Electrical power (P), which is expressed in Watts (W), delivered to the body is the product of current (I) and voltage (V) received. Thus:

P = I x V           ---------------------(ii)

Where;

I equates to 0.075A   [as derived above]

V is 120V     [as outlined in the question]

Plugging these values into equation (ii):

P = 0.075 x 120

P = 9W

Hence, the electrical power received by your body is 9W