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ch4aika
2 months ago
6

A student solving a physics problem for the range of a projectile has obtained the expression r= v20sin(2θ)g where v0=37.2meter/

second, θ=14.1∘, and g=9.80meter/second2. use your calculator to evaluate r.

Physics
2 answers:
kicyunya [3.2K]2 months ago
6 0

The projectile’s range is approximately 66.7 meters

\texttt{ }

Additional explanation

Acceleration represents the rate at which velocity changes.

\boxed {a = \frac{v - u}{t} }

\boxed {d = \frac{v + u}{2}~t }

Definitions:

a = acceleration (m/s²)

v = final velocity (m/s)

u = initial velocity (m/s)

t = time elapsed (s)

d = distance traveled (m)

\texttt{ }

The formula for the range of a projectile is:

\boxed{ R = \frac{ v_o^2 \sin 2\theta}{g} }

Where:

R = projectile range (m)

v₀ = initial velocity (m/s)

θ = launch angle

g = gravitational acceleration (m/s²)

Let's solve the given problem now!

\texttt{ }

Given:

Initial velocity v₀ = 37.2 m/s

Launch angle θ = 14.1°

Gravity g = 9.80 m/s²

Find:

The projectile’s range R = ?

Solution:

R = \frac{ v_o^2 \sin 2\theta}{g}

R = \frac{ 37.2^2 \sin 2 (14.1^o)}{9.80}

\boxed {R = 66.7 \texttt{ m}}

\texttt{ }

Hence, the projectile’s range is approximately 66.7 meters

\texttt{ }

Learn more:

  • Runner's Velocity: brainly.com/question/3813437
  • Kinetic Energy: brainly.com/question/692781
  • Acceleration: brainly.com/question/2283922
  • Car Speed: brainly.com/question/568302

\texttt{ }

Answer details

Grade: High School

Subject: Physics

Topic: Kinematics

ValentinkaMS [3.4K]2 months ago
5 0

The formula for range is:

R = \frac{v_o^2 sin2\theta}{g}

Given values are:

v_0=37.2m/s

where θ equals 14.1 degrees

g=9.80m/s^2

Using the equation above,

R = \frac{37.2^2 sin2*14.1}{9.80}

The calculated range is 66.7 meters.

Therefore, the range is approximately 66.1 meters.

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