A student solving a physics problem for the range of a projectile has obtained the expression r= v20sin(2θ)g where v0=37.2meter/

Question

ch4aika

3 months ago

6

A student solving a physics problem for the range of a projectile has obtained the expression r= v20sin(2θ)g where v0=37.2meter/

second, θ=14.1∘, and g=9.80meter/second2. use your calculator to evaluate r.

Physics

2 answers:

kicyunya [3.2K] · Answer 1 · 2026-02-17T20:07:14+03:00

The projectile’s range is approximately 66.7 meters

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Additional explanation

Acceleration represents the rate at which velocity changes.

$\boxed {a = \frac{v - u}{t} }$

$\boxed {d = \frac{v + u}{2}~t }$

Definitions:

a = acceleration (m/s²)

v = final velocity (m/s)

u = initial velocity (m/s)

t = time elapsed (s)

d = distance traveled (m)

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The formula for the range of a projectile is:

$\boxed{ R = \frac{ v_o^2 \sin 2\theta}{g} }$

Where:

R = projectile range (m)

v₀ = initial velocity (m/s)

θ = launch angle

g = gravitational acceleration (m/s²)

Let's solve the given problem now!

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Given:

Initial velocity v₀ = 37.2 m/s

Launch angle θ = 14.1°

Gravity g = 9.80 m/s²

Find:

The projectile’s range R = ?

Solution:

$R = \frac{ v_o^2 \sin 2\theta}{g}$

$R = \frac{ 37.2^2 \sin 2 (14.1^o)}{9.80}$

$\boxed {R = 66.7 \texttt{ m}}$

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Hence, the projectile’s range is approximately 66.7 meters

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Learn more:

Runner's Velocity: brainly.com/question/3813437
Kinetic Energy: brainly.com/question/692781
Acceleration: brainly.com/question/2283922
Car Speed: brainly.com/question/568302

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Answer details

Grade: High School

Subject: Physics

Topic: Kinematics

ValentinkaMS [3.4K] · Answer 2 · 2026-02-17T20:06:49+03:00

ValentinkaMS [3.4K]3 months ago

5 0

The formula for range is:

$R = \frac{v_o^2 sin2\theta}{g}$

Given values are:

$v_0=37.2m/s$

where θ equals 14.1 degrees

$g=9.80m/s^2$

Using the equation above,

$R = \frac{37.2^2 sin2*14.1}{9.80}$

The calculated range is 66.7 meters.

Therefore, the range is approximately 66.1 meters.