The new pressure of the gas is calculated to be 40.7 kPa. Using the principle that P1 • V1 = P2 • V2, we can set 98.8 kPa (P1) multiplied by 21.7 mL (V1) equal to P2 (unknown pressure) multiplied by 52.7 mL (V2). To isolate P2, we rearrange the equation to P2 = (98.8 kPa • 21.7 mL) / 52.7 mL, resulting in P2 equal to 40.7 kPa.
The gravimetric factor for Ag2O within AgS amounts to 0.1078.
Response:
The conclusion to your inquiry is Pressure 1 = 1.73 atm
Clarification:
Data provided
Volume 1 = 5 l
Pressure 1 =?
Volume 2 = 12 l
Pressure 2 = 0.72 atm
Procedure
To resolve this issue, Boyle's law is applied
Pressure 1 x Volume 1 = Pressure 2 x Volume 2
-Finding Pressure 1
Pressure 1 = Pressure 2 x Volume 2 / Volume 1
-Replace values
Pressure 1 = 0.72 x 12 / 5
-Calculating
Pressure 1 = 8.64/5
-Final outcome
Pressure 1 = 1.73 atm
