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laiz
1 month ago
5

Which answer helps to explain why carbon atoms tend to make 4 covalent bonds? which answer helps to explain why carbon atoms ten

d to make 4 covalent bonds? the valence shell needs 8 electrons. the first electron shell has 4 orbitals. the carbon nucleus has 4 protons. all of the above. none of the above; carbon makes 3 covalent bonds?
Chemistry
2 answers:
castortr0y [3K]1 month ago
8 0

La configuración electrónica del carbono-12 es: 1s2-2s2-2p2. Según esta configuración, la respuesta correcta es: la primera capa de electrones tiene 4 orbitales.


castortr0y [3K]1 month ago
3 0

Los átomos de carbono suelen formar 4 enlaces covalentes porque la capa de valencia necesita 8 electrones. Para que los átomos sean estables, es necesario que sus capas de energía externas, denominadas capas de valencia, estén completas. Este principio se conoce como la regla del octeto. Solo los gases nobles (Grupo 8) poseen capas de valencia llenas de forma natural, lo que los convierte en elementos estables. Los demás átomos tienden a perder, ganar o compartir electrones para alcanzar la misma configuración electrónica que estos gases nobles. Los metales tienden a ceder electrones a los no metales, que normalmente los aceptan. El resultado de esta transferencia de electrones se denomina enlace iónico. Por otra parte, los no metales tienden a compartir electrones entre sí, formando enlaces covalentes.

EXPLICACIÓN ADICIONAL

La primera capa de electrones tiene 4 orbitales.

FALSO La distribución de los electrones en el átomo de carbono se presenta en la siguiente configuración electrónica:

1s^2 \ 2s^2 \ 2p^2

Los coeficientes indican la capa electrónica y el superíndice muestra la cantidad de electrones en los orbitales. En el caso del carbono, hay solo dos capas electrónicas con electrones: la primera capa cuenta con el orbital s y la segunda con el orbital s y tres orbitales p.

Por lo tanto, el carbono solo tiene un orbital en la primera capa electrónica.

El núcleo de carbono tiene 4 protones.

FALSO La cantidad de protones en un átomo es lo que le da su identidad única. El número de protones se conoce como número atómico. El número atómico del carbono es 6. Por lo tanto, su núcleo contiene 6 protones. El átomo con 4 protones es Boro (B).

Todos los anteriores

FALSO Dos de las afirmaciones anteriores no son verdaderas.

El carbono forma 3 enlaces covalentes

FALSO El carbono forma 4 enlaces covalentes porque puede compartir 4 electrones no apareados con otros átomos. Puede formar enlaces covalentes simples, dobles o triples con otros átomos de carbono.

MÁS INFORMACIÓN

• Energía de Ionización

• Número Atómico

• Compuesto Iónico

Palabras clave: regla del octeto, electrones de valencia, configuración electrónica

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The net ionic equation for the reaction between chromium (III) hydroxide and nitrous acid is:

Cr(OH)₃ (s) + 3H⁺ (aq) ⇒ Cr³⁺ (aq) + 3H₂O (l)

Additional Details

An electrolyte dissociates into ions in solution.

Chemical equations can also be represented with ionic species.

Strong electrolytes (fully ionized) are written as separate ions, whereas weak electrolytes (partially ionized) remain as intact molecules.

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Removing these spectators results in the net ionic equation.

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Therefore, only dissolved compounds are represented by their ions (aq).

The problem involves chromium (III) hydroxide reacting with nitrous acid.

The reaction occurring is:

Cr(OH)₃ (s) + 3HNO₂ (aq) ⇒ Cr(NO₂)₃ (aq) + 3H₂O (l)

Chromium (III) hydroxide is a solid and remains un-ionized, as does water.

Thus, the ionic equation is:

Cr(OH)₃ (s) + 3H⁺ (aq) + 3NO₂⁻ (aq) ⇒ Cr³⁺ (aq) + 3NO₂⁻ (aq) + 3H₂O (l)

The ion 3NO₂⁻ is a spectator ion; removing it yields the net ionic equation:

Cr(OH)₃ (s) + 3H⁺ (aq) ⇒ Cr³⁺ (aq) + 3H₂O (l)

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Response: k = 23045 N/m

Clarification:

To determine the spring constant, one must consider the maximum elastic potential energy that the spring can withstand. The kinetic energy of the vehicle should equal at minimum the elastic potential energy of the spring when it is fully compressed. Hence, we express it as:

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v: car speed = 8 km/h

x: maximum spring compression = 1.5 cm = 0.015m

You need to resolve equation (1) for k. Beforehand, convert the speed v to meters per second:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant calculates to 23045 N/m

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Answer:

The temperature of a vessel at a pressure reading of 1.250 atm is 296.43 K.

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P_1=1.000 atm, T_1=298.15K

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Applying Gay Lussac's law:

\frac{P_1}{T_1}=\frac{P_2}{T_2} (When volume is constant)

\frac{1.000 atm}{273.15 K}=\frac{1.250 atm}{T_2}

T_2=296.43 K

At a pressure of 1.250 atm, the temperature of the vessel is 296.43 K.

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Answer:

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Explanation:

Greetings,

Upon analyzing the significant figures, it's evident that 1 g has merely one significant figure. Consequently, among the provided choices, we should go with the one that closely matches this, hence the right answer is B 1.0 g since this measurement fits the required value.

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