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klemol
4 months ago
14

The [H3O+] in a solution is increased to twice the original concentration. Which change could occur in the pH? 2.0 to 4.0 1.7 to

1.4 5.0 to 2.5 8.5 to 6.5 6.8 to 9.8
Chemistry
2 answers:
KiRa [2.9K]4 months ago
8 0
Answer: second option: 1.70 to 1.40

Explanation:

1) pH is defined using the formula pH = - log [H₃O⁺]

2) Given that the initial concentration is x and after doubling it becomes 2x, we calculate:

pHi = - logx
pHf = - log 2x = - log 2 - logx

Thus, pHf - pHi = - log2 - logx - (- logx) = - log2 ≈ - 0.30

⇒ pHi - pHf = 0.30, indicating that the final pH (with twice the hydronium ions) is 0.30 lower than the starting pH.

3) The only option that indicates a 0.30 decline in pH is the second one: from 1.70 to 1.40. Therefore, that is the correct choice.


castortr0y [3K]4 months ago
3 0
The possible change in pH given that the [H3O+] in the solution has been raised to double the initial concentration is 1.70 to 1.40
The formula for pH is - log [H₃O⁺]



pHi = - logx
pHf = - log 2x = - log 2 - logx
- log2 is approximately - 0.30
Thus, pHi - pHf = 0.30
This results in a pH decrease of 0.30.
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