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adelina 88
5 days ago
7

a 5.00 L sample of helium expands to 12.0 L at which point the pressure is measured to be 0.720atm. what was the original pressu

re of the gas
Chemistry
1 answer:
lorasvet [2.6K]5 days ago
5 0

Response:

The conclusion to your inquiry is Pressure 1 = 1.73 atm

Clarification:

Data provided

Volume 1 = 5 l

Pressure 1 =?

Volume 2 = 12 l

Pressure 2 = 0.72 atm

Procedure

To resolve this issue, Boyle's law is applied

                 Pressure 1 x Volume 1 = Pressure 2 x Volume 2

-Finding Pressure 1

                 Pressure 1 = Pressure 2 x Volume 2 / Volume 1

-Replace values

                 Pressure 1 = 0.72 x 12 / 5

-Calculating

                Pressure 1 = 8.64/5

-Final outcome

                 Pressure 1 = 1.73 atm

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