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Vinil7
20 days ago
5

An experiment will be conducted in which 20 pepper plants are randomly assigned to two groups. The plants in Group 1 will receiv

e the current fertilizer, Fertilizer A, and the plants in Group 2 will receive a new fertilizer, Fertilizer B. All other growing conditions, including amount of sunlight and water, will be kept the same for the two groups. The growth of the pepper plants will be compared for the two groups. What are the experimental units in this experiment?
The two types of fertilizer

a.The sunlight and amount of water
b.The 10 plants in Group 1
c.The 10 plants in Group 2
d.The 20 plants in the two groups
Mathematics
1 answer:
Svet_ta [9.4K]20 days ago
5 0

Response:

d

Detailed explanation:

Solution:

The experimental unit refers to the physical entity to which a treatment can be randomly assigned. (In this case, we're analyzing the effects of two types of fertilizers, Type A and Type B, on the plants.)

- It is generally a single animal or plant. The experimental unit constitutes the basis of statistical analysis. (The analysis is performed on the plants separated into two groups: Group 1 and Group 2).

- Nonetheless, the experimental units must be capable of receiving differing treatments. (Group 1 - Type A fertilizer) & (Group 2 - Type B fertilizer).

Response: The experimental units are the two groups (Group 1 and Group 2), each containing 20 plants.

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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Zina [9164]

Answer:

Step-by-step reasoning:

(a)

To have an accepted bid, it needs to exceed $10,000. Let bid x be a continuous random variable uniformly distributed between

$10,000 and $15,000

The range for accepted bidding is [ {\rm{\$ 10,000, \$ 15,000}], with b = $15000 and a = $10000.

The provided bidding range is [$10,000,$12,000]. The probability is determined as follows,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The accepted bidding range is [$10,000,$15,000], where b = $15,000 and a =$10,000. The given bidding range is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The optimal amount to bid for maximizing the probability of acquiring the property is calculated as,  

The accepted bidding range is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The provided bidding range is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  If you know someone willing to pay you $16,000 for the property, would you still consider bidding less than the amount mentioned in part (c)? Why or why not?

5 0
5 days ago
Point T is the midpoint of RS, W is the midpoint of RT, and Z is the midpoint of WS. If the length of TZ is x, find the lengths
PIT_PIT [9117]

Let RS be denoted as y.

Given that T is the midpoint of RS, this results in RT = TS = \frac{y}{2}

And W acting as the midpoint of RT, leads to

thus RW = WT = \frac{\frac{y}{2} }{2} = \frac{y}{4}

Given that Z is the midpoint of WS.

Meaning WZ = ZS = \frac{WS}{2} = \frac{WT+TS}{2} = \frac{(\frac{y}{4} +\frac{y}{2} )}{2} =\frac{3y}{8}

Consequently, TZ = TS - ZS = \frac{y}{2} -\frac{3y}{8} = \frac{4y-3y}{8} = \frac{y}{8}

However, TZ is defined as x.

Thus, \frac{y}{8} = x

y = 8x = RS.

A) Length of RW = \frac{y}{4} = \frac{8x}{4} = 2x

B) Length of WZ = \frac{3y}{8} =\frac{3*8x}{8} = 3x

C) Length of RS = y = 8x

D) Length of ZS = WZ = 3x.

An image is provided for clarification.

8 0
3 days ago
Which shows the factored form of x2 – 12x – 45?
AnnZ [9099]
Hello!

(x+a)·(x+b) equals x²+xa+xb+ab which simplifies to x²-12x-45

x² equals x²
xa+xb can be expressed as (a+b)x = -12x thus, (a+b) = -12
ab equals -45

Under what conditions do (a+b) equal -12 and ab equal -45?

+3-15 results in -12 while (+3)(-15) gives -45
-3-15 yields -18 and (-3)(-15) results in +45
+3+15 produces +18 and (+3)(+15) also equal to +45
-3+15 equals +12 and (-3+15) results in -45

Conclusion:

(x+3)(x-15) 



6 0
11 days ago
Read 2 more answers
The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be used to find
Svet_ta [9496]

Response: Using the Pythagorean theorem, we can set up the equation as 14^2=9^2+x^2

                                     -9^2    -9^2

Thus, our equation simplifies to

x^2=14^2-9^2

8 0
5 days ago
Read 2 more answers
2.6 Puzzle time how can you make sure to start a fire with two sticks?
Svet_ta [9496]

Answer:

"Ensure that one of them is a match"

Step-by-step explanation:

Generating heat through friction requires some practice. By elevating the wood's temperature, it's feasible to reach the necessary ignition temperature.

Successful fire-starting depends on proper technique and equipment. Failures often arise from inadequate approach and gear, which can complicate the learning process.

When selecting wood, aim for the following criteria:

  • Dry tinder
  • Wood should be compressible; if it isn't, it's too challenging.
  • Wood that is moderately strong but not overly tough
  • Avoid sap in the wood

Position the two pieces of wood at a 90-degree angle, resembling a cross. Support one stick vertically on the ground, while the other rubs against it quickly, using intervals.

Underneath, place dry tinder that catches fire swiftly after it's ignited.

For the Puzzle, remember the order of the words:

Ensure that one of them is a match.

Utilize tree wood, apply friction and heat until ignition occurs.

5 0
26 days ago
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