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aleksklad
12 days ago
8

8.5b−3.4∙(13a−3.2b)+a

Mathematics
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CRITICAL THINKING A local zoo employs 36 people to take care of the animals each day. At most, 24 of the employees work full tim
lawyer [12517]
We consider all workers as either full-time or part-time. 36 = 24 + 12 If there are 24 or fewer full-time workers, there must be at least 12 part-time workers. (This conclusion is based on the understanding of sums.) You can formulate the inequality in two steps. First, present and resolve an equation for full-time workers in relation to part-time workers. Then, apply the specified limit on full-time workers. This results in an inequality that can be solved for part-time workers. Let f and p represent full-time and part-time positions, respectively. f + p = 36... given f = 36 - p... subtract p to express f in terms of p. f ≤ 24......... given (36 - p) ≤ 24.... substitute for f. This gives your inequality in terms of p. 36 - 24 ≤ p.... rearranging gives p ≥ 12........ this is the solution to the inequality
5 0
1 month ago
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
Leona [12618]

To address this problem, let's start by formulating the general motion equation along the vertical direction.

This gives us:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • g: gravitational acceleration
  • vo: initial velocity
  • h0: starting height

For the first individual:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second individual:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

When both individuals reach the identical altitude, the following holds:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rearranging results in:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Solving for time:

t = 29 (\frac {12} {19})\\t = 18.31s

Result:

The two window washers reach the same height after 18.31 seconds.

6 0
3 months ago
Read 2 more answers
A bicyclist travels at a constant speed of 12 miles per hour for a total of 45 minutes. (Use set notation for the domain and ran
Inessa [12570]
A cyclist maintains a consistent speed of 12 miles per hour over a period of 45 minutes. We apply the formula, Distance = speed * time With a constant speed of 12, it reflects a linear relationship. The equation is represented as d = 12t, where t stands for time and d signifies distance. At the origin, t=0 and distance d=0. At the conclusion, t=45 min = 0.75 hours and consequently, distance is 12 * 0.75 = 9. Thus, the domain (t) is { } Range (d) is { }
5 0
1 month ago
Read 2 more answers
Pepita and francisco each spend a equal amount of time on homework. The table shows the fraction of time they spend on each subj
Zina [12379]

Answer:

\begin{array}{ccc}\text{Homework}&\text{Pepita}&\text{Francisco}\\ \\\text{Math}&\dfrac{1}{6}&\dfrac{1}{2}\\ \\\text{English}&\dfrac{2}{3}&\dfrac{1}{8}\\ \\\text{Science}&\dfrac{1}{6}&\dfrac{3}{8}\end{array}

Step-by-step explanation:

Pepita and Francisco allocate equal amounts of time to their homework. The table indicates how they distribute their time across various subjects.

\begin{array}{ccc}\text{Homework}&\text{Pepita}&\text{Francisco}\\ \\\text{Math}&&\dfrac{1}{2}\\ \\\text{English}&\dfrac{2}{3}&\\ \\\text{Science}&\dfrac{1}{6}&\dfrac{3}{8}\end{array}

Pepita dedicated

\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{2\cdot 2+1\cdot 1}{6}=\dfrac{5}{6}

to English and Science.

Thus, she utilized

1-\dfrac{5}{6}=\dfrac{6}{6}-\dfrac{5}{6}=\dfrac{1}{6}

for Math.

On the other hand, Francisco spent

\dfrac{1}{2}+\dfrac{3}{8}=\dfrac{1\cdot 4+3\cdot 1}{8}=\dfrac{7}{8}

on Math and Science, resulting in him spending

1-\dfrac{7}{8}=\dfrac{8}{8}-\dfrac{7}{8}=\dfrac{1}{8}

on English.

The table displays:

\begin{array}{ccc}\text{Homework}&\text{Pepita}&\text{Francisco}\\ \\\text{Math}&\dfrac{1}{6}&\dfrac{1}{2}\\ \\\text{English}&\dfrac{2}{3}&\dfrac{1}{8}\\ \\\text{Science}&\dfrac{1}{6}&\dfrac{3}{8}\end{array}

5 0
2 months ago
A researcher claims that the mean cost of raising a child from birth to age 2 by husband­wife families in the U.S. is $13,960. A
Zina [12379]

Answer:

Yes, sufficient evidence exists to reject the proposal.

Step-by-step explanation:

This requires a single mean test to determine if the average expense of raising a child from birth to age 2 by husband-wife families in the U.S. is $13,960.

The hypotheses are:

H₀: The average expense of raising a child from birth to age 2 by husband-wife families in the U.S. is $13,960, or µ = $13,960.

Hₐ: The average expense of raising a child from birth to age 2 by husband-wife families in the U.S. differs from $13,960, or µ ≠ $13,960.

Provided is the summary of information:

\ar x=13725\\\sigma=2345\\n=500\\\alpha =0.10

The computed test statistic is:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{13725-13960}{2345/\sqrt{500}}=-2.24

The test statistic equals -2.24.

We will determine the p-value for this test statistic at a 10% significance level using the following calculations:

p-value=2\times P(Z

               =2\times 0.01255\\=0.0251

Consult the z-table.

The calculated p-value stands at 0.0251 < 0.10, prompting the null hypothesis to be rejected.

Conclusion:

Since the null hypothesis has been rejected at the 10% significance level, it can be concluded that sufficient evidence exists to refute the claim.

The average expense of raising a child from birth to age 2 by husband-wife families in the U.S. does not equal $13,960.

5 0
1 month ago
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