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20 days ago

6

Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $

1.25 for a delivery made within 1 1/2 mi, $1.70 for a delivery of at least 1 1/2 mi but less than 1 3/4 mi, $2.15 for a delivery of at least 1 3/4 mi but less than 2 miles, and so on. If tim raised his rates by 10% what would he be paid to deliver a package 3 1/8 miles

1 answer:

tester [8.8K]20 days ago

6 0

Answer:

$4.84

Explicación paso a paso:

Dado lo siguiente

Por la entrega dentro de $1\frac{1}2$ mi, el cargo es = $1.25

Por la entrega dentro de $1\frac{1}2$ mi - $1\frac{3}4$ mi, el cargo es = $1.70

Por la entrega dentro de $1\frac{3}4$ mi - 2 mi, el cargo es = $2.15

y

así sucesivamente.

O sea,

Por la entrega dentro de 2 mi - 2 $\frac{1}4$ mi, el cargo es = $2.60

Por la entrega dentro de 2 $\frac{1}4$ mi - 2 $\frac{1}2$ mi, el cargo es = $3.05

Por la entrega dentro de 2 $\frac{1}2$ mi - 2 $\frac{3}4$ mi, el cargo es = $3.50

Por la entrega dentro de 2 $\frac{3}4$ mi - 3 mi, el cargo es = $3.95

Por la entrega dentro de 3 mi - 3 $\frac{1}4$ mi, el cargo es = $4.40

Así que, cada 0.25 mi o $\frac{1}4$ mi, el costo incrementa en $0.45.

Se indica un aumento del 10% en las tarifas.

Es decir, por cada incremento de 0.25 mi, se suma 0.45*1.10 = $0.495 a los cargos.

La distancia de $3\frac{1}8$ millas está dentro del rango de 3 mi - 3 $\frac{1}4$ mi.

Por lo tanto, los cargos reales tras el incremento del 10% son

$\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}$

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Answer:

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Explicación paso a paso:

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25 days ago

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Response:

$(6,-8)$ .

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We have a set of equations provided. Our task is to find the solution for this system.

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Starting from equation (2), we will derive:

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Next, by inserting this value into equation (1), we will achieve:

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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

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Answer:

Attached is the question in consideration.

$m\angle CEA =90 \ (deg)$

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Step-by-step explanation:

⇒ Given that $\ ray\ AE$ is ⊥ $FEC$ it constitutes a right triangle, leading to $m\angle CEA =90\ (deg)$ .

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it surpasses $180\ (deg)$ while $\angle CEF$ is a

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Response:

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