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Verdich
20 days ago
6

Fifty people enter a contest in which three identical prizes will be awarded. in how many different ways can the prizes be award

ed to the entrants? explain how you would solve the problem.
Mathematics
2 answers:
Zina [9.1K]20 days ago
4 0

I utilized the combination of 50 as the total and 3 as the selection to arrive at the answer of 19600. I took the test and confirmed it was accurate.


zzz [9K]20 days ago
4 0
<span>Given that each individual can receive a single prize, there are 50*49*48= 117600 different ways to allocate the prizes. The first award can be given to any of the 50 participants, the second to one of the remaining 49, and the last to one of the leftover 48. Multiplying these options together provides the solution.</span>
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The correct choice is option D. The given equations are:...[1]...[2] Multiply equation [1] by 5 on both sides; we have...[3]. By using the elimination method, we can add equations [2] and [3] to eliminate y and determine x, resulting in... Dividing both sides by 13 yields x = 3. Substituting x back into equation [1] results in 2(3) - y = -4, which simplifies to 6 - y = -4. After subtracting 6 from both sides, we find -y = -10. Dividing through by -1 gives y = 10. Hence, the solution is (3, 10). Consequently, a valid equation that can replace 3x + 5y = 59 in the original set while still yielding the same result is 13x = 39.
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9 days ago
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Answer and explanation:

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Algebra can also manifest itself in expressions, commonly referred to as algebraic expressions, which can be incorporated into equations, such as the previously mentioned 2a = $50. These expressions may take forms like 2a + 3b, where a and b designate the costs of different products that were acquired in quantities of 2 and 3, respectively.

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Consider the next 1000 98% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on whi
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d) Both blocks experienced equivalent energy loss due to friction

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Energy loss from friction is E(X) = np

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2 days ago
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14 days ago
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